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Amanda [17]
4 years ago
12

Which planet, when viewed through a telescope, appears as a reddish ball interrupted by some permanent dark regions that change

intensity?
Physics
2 answers:
Misha Larkins [42]4 years ago
8 0

Answer: Mars

Explanation:

Mars is known as red planet. It is the fourth planet from sun and second smallest planet after Mercury. It has two moons- Phobos and Deimos. Its surface is composed of iron oxide and that is why it appears reddish when viewed from telescope. The appearance is interrupted by some permanent dark regions that changes intensity. These are Albedo features visble on Mars.

Andrej [43]4 years ago
4 0
The answer should be Mars. 
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5 0
2 years ago
Two satellites orbit the Earth in circular orbits of the same radius. One satellite is twice as massive as the other. Which stat
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To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.

This concept is expressed in the equation,

v = \sqrt{\frac{Gm_E}{r}}

Where,

G = Universal Gravitational constant

m_E = Mass of the Earth

Therefore the ratio of the velocity from two satellites is,

\frac{v_1}{v_2} = \sqrt{\frac{r_2}{r_1}}

The ratio between the two satellites is the same, then

\frac{v_1}{v_2} = \sqrt{\frac{r}{r}}

\frac{v_1}{v_2} = 1

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Therefore the correct option is B.

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3 years ago
Is the wood from trees a electrical conductor or electric insulator
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A wire runs left to right and carries a current in the direction shown. What is the direction of the magnetic field at point Z?
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3 years ago
Read 2 more answers
If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)
worty [1.4K]

Answer: \sqrt{2}

The linear momentum p is given by the following equation:

p=m.v   (1)

Where m is the mass and v the velocity.

On the other hand, the kinetic energy K is given by:

K=\frac{p^{2}}{2m}   (2)

Which is the same as:

K=\frac{1}{2}m.v^{2}

Now, if we double the kinetic energy, equation (2) changes to:

2K=2\frac{p^{2}}{2m}  

2K=\frac{p^{2}}{m}   (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of \sqrt{2} or 2^{1/2}:

Applying this in (2):

K=\frac{(\sqrt{2}p)^{2}}{2m}

K=\frac{(2p)^{2}}{2m}

K=\frac{p^{2}}{m}>>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

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3 years ago
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