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Nastasia [14]
3 years ago
10

What is a unit rate?

Mathematics
2 answers:
Semmy [17]3 years ago
7 0

Answer:

The numbers or measurements being compared are called the terms of the ratio. A rate is a special ratio in which the two terms are in different units. ... When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates.

Step-by-step explanation:

sergeinik [125]3 years ago
5 0

Answer:

Unit rate is used to compare quantities in which the second quantity is one. Common examples of unit rate would include, miles per hour earnings per hour cost per gallon.

Step-by-step explanation:

It's also your rise over run, remember to look at the unit of measurement when counting. Example, If rise over run is 1Mile/15min. That's a unit rate.

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Circle e has a radius of 40 inches with m arc ABC=324 degrees. Find the exact length of arc ABC.
creativ13 [48]
The formula to find the Length of the arc = (2r) (θ / 360°)
Substituting the values
Length of the arc = (2) (40) (324° / 360°)
By further calculation
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So we get
= (80) (3.14) (0.9)
= 226.08 cm.
Therefore, the length of the arc is 226.08 cm.

Hope this helps
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2 years ago
Please answer quickly
olchik [2.2K]

Answer:

a and c I think if I'm wrong I will try again

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2 years ago
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Story Problems
Gnom [1K]
Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars  
We have Lesley's purchase: 4x+2y=13.50
 And Landon's: 1x+5y=17.55 
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 x+15.75=17.55
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 Problem 4.
 Let w = number of wood bats sold
 Let m = number of metal bats sold
 
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6 0
3 years ago
Read 2 more answers
If the demand function for a commodity is given by the equation
Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\

q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13

replace p in any equation and

q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92

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3 years ago
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3 years ago
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