

Hence, Jake's running time in decimal is: 3.2 hours
Answer:segment YZ ≈ 19.4 inangle X ≈ 85.3°angle Z ≈ 26.7°Explanation:1) Given two side lenghts and one angle you can use sine law:

2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:

From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:

From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
Answer:
Step-by-step explanation:
Solve the inequality 5x − 4y > 20 for y, as follows: Subtract 5x from both sides, obtaining:
-4y > 20 - 5x;
Then divide all terms by -4:
y < -5 +(5/4)x, where the direction of the inequality sign has been reversed because of division by a negative quantity.
Temporarily replace the < symbol with = obtaining y = -5 +(5/4)x. Now choose at least three x values and find the corresponding y values. For example:
x y = -5 +(5/4)x
0 -5
4 0
-8 -15
Now plot these three points (0, -5), (4, 0) and (-8, -15). Draw a dashed line through them. Because of the < symbol in y < -5 +(5/4)x, shade the area underneath the dashed line.
Answer:
54 beads
Step-by-step explanation:
1 hexagon = 6
2 hexagons = 10
3 hexagons = 14
Based on the pattern shown above +4 you can create an equation from this to help support finding the amount.
y = 4x + 6
y - total amount
4x - amount that is added by
6 - initial amount for 1 hexagon
Based on this you plug in 12 into x and you will find the answer:
y = 4(12) + 6
= 48 + 6
= 54
If you need to check the work honestly drawing it out, but this equation can also be supported based on the 3rd diagram of hexagon, where the initial is 6 and then 4 are added each time afterwards!!!
Answer:
Because square root is essentially the same thing as the power to a half
sqrt(x) is the same as (x)^1/2