The 7th term of the sequence to the nearest thousandth is 223.949
<h3>What are geometric sequences?</h3>
These are sequence that increases in an exponential form.
The formula for calculating the nth term of a geometric sequence is expressed as:
Tn = ar^n-1
Given the following parameters
a = 75
r = 1.2
n = 7
Substitute the given parameter into the formula
T7 = 75(1.2)^6
T7 = 223.949
Hence the 7th term of the sequence to the nearest thousandth is 223.949
Learn more on geometric sequence here: brainly.com/question/9300199
Answer:
The function y = sec(x) shifted 3 units left and 7 units down .
Step-by-step explanation:
Given the function: y = sec(x)
- If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.
- If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.
The function
comes from the base function y= sec(x).
Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.
Therefore, the transformation on the given function is shifted 3 units left and 7 units down
Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45