The distance between the plane and house 1 is 4899.2 feet
<h3>How to determine the distance between the plane and house 1?</h3>See attachment for illustration of the question, where x represents the distance between the plane and house 1
Start by calculating the angle A using:
A = 180 - 17.5 - 18.8 ----- (angles in a triangle theorem)
This gives
A = 143.7
The distance x is then calculated using the following sine theorem
a/sin(A) = b/sin(B) = c/sin(C)
Using the parameters in the diagram, we have:
x/sin(18.8) = 9000/sin(143.7)
Multiply both sides by sin(18.8)
x= sin(18.8) * 9000/sin(143.7)
Evaluate
x = 4899.2
Hence, the distance between the plane and house 1 is 4899.2 feet
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Answer:
Step-by-step explanation:
Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) .
We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63
b = ±√(a² - c²)
= ±√(91² - 63²)
= ±√(8281 - 3969)
= ±√4312
= ±14√22
So the equation is