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Nuetrik [128]
2 years ago
12

People from two houses 9,000 feet apart are looking up at a plane that is BETWEEN them. House 1 is west of the plane has an angl

e of elevation of 17.5 degrees and house 2 is east of the plane and has an angle of elevation that is 18.8 degrees. How far is the plane from House 1?
Mathematics
1 answer:
katovenus [111]2 years ago
4 0

The distance between the plane and house 1 is 4899.2 feet

<h3>How to determine the distance between the plane and house 1?</h3>

See attachment for illustration of the question, where x represents the distance between the plane and house 1

Start by calculating the angle A using:

A = 180 - 17.5 - 18.8 ----- (angles in a triangle theorem)

This gives

A = 143.7

The distance x is then calculated using the following sine theorem

a/sin(A) = b/sin(B) = c/sin(C)

Using the parameters in the diagram, we have:

x/sin(18.8) = 9000/sin(143.7)

Multiply both sides by sin(18.8)

x= sin(18.8) * 9000/sin(143.7)

Evaluate

x = 4899.2

Hence, the distance between the plane and house 1 is 4899.2 feet

Read more about angle of elevation at:

brainly.com/question/88158

#SPJ1

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Answer:

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Step-by-step explanation:

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We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

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So the equation is

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After you pick and eat the apple, there are 10-1 = 9 pieces of fruit left. Also, the probability of picking a peach is 4/9, as there are 4 peaches out of 9 fruit left over.

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Using a calculator, 4/15 = 0.267 approximately.

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Answer:

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