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earnstyle [38]
3 years ago
5

Write an equation of the line whose slope is 1/3 and whose y-intercept is 2.

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0
This formula is called “slope intercept form”

The formula looks thin this: y=mx+b.

m=Slope
b= y-Intercept

In our problem, our m (slope) = 1/3 and our b (y-intercept) = 2

So our answer for this would be y=1/3x + 2.
Artyom0805 [142]3 years ago
5 0
Y=1/3x+2
I hope this is right
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I have 2 Questions.
aleksandr82 [10.1K]

Answer:

looks hard omgong

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3 years ago
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A water gauge in a pond measured 2358 in. At the beginning of the week. After five days of rain, the gauge read 3414 in. By how
V125BC [204]

Answer:

1056 inches

Step-by-step explanation:

Given that :

Initial measurement = 2358 in

Guage level after 5 days of rain (final reading) = 3414 in

Change in water level rise :

Final reading - Initial reading

(3414 - 2358) in

= 1056 inches

3 0
3 years ago
How can I do this plz help me
Dvinal [7]

Answer:

0.3030

Step-by-step explanation:

divide 10 b y 33

6 0
3 years ago
Read 2 more answers
(look at image) can i get help with these two?
serg [7]

Answer:

1. x = 2, AC = 30, AB - 4

2. y = 4, AB = 34, BC = 34

Step-by-step explanation:

1. AB + BC = AC so 26 + (10 - 3x) = 14x +2 and then add 3x to both sides and subtract 2 from both sides to get x on one side and an integer on the other side which is 34 = 17x and then divide 17 from both sides to get x = 2 and then substitute x into the AC and AB equations to find the values its equal to.

2. The symbol in the given means that the two lengths are congruent which means they are equal to each other so you put the two equations equal to each other and solve for y. 9y -2 = 14 + 5y, so subtract 5y from both sides and add two to both sides to get 4y = 16 and then divide both sides by 4 to get y = 4 and then substitute in the answer to find the lengths of AB and BC.

6 0
3 years ago
Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2
Leviafan [203]

we are given

r(t)=(7t,3cos(t),3sin(t))

we can find x , y and z

x=7t,y=3cos(t),z=3sin(t))

now, we can use arc length formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

now, we can find derivative

x'=7,y'=-3sin(t),z'=3cos(t))

now, we can plug values

and we get

L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt

L=\int _{-2}^2\sqrt{7^2+9}dt

=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)

L=4\sqrt{58}...........Answer


8 0
4 years ago
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