Solve for b?
1. Distribute “4(4b+3)” and “3(6-11)”
16b+12+2b=18-33
2. combine like terms
18b+12=-15
18b=-27
b=-27/18
3. simplify
b=3/2
Answer: (-2,1)
Step-by-step explanation:
Answer is about 3 times
About 3 times in April bc it’s saying It rained two times out of the 12 days in March in there about 30 days in March and 30 days in April so if you just add 12 and 12 equals 24 so it rained 4 times but if you are 12 it would equal 36 so if you would take half of 12 which is sixto equal one rainy day it would give you about 3 days
Answer:
4 days
Step-by-step explanation:
We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.
P(x>3 cargo ships) = 1-P(x<=3)
P(x>3) = 1-P(x<=3)
P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]
![P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]](https://tex.z-dn.net/?f=P%28x%3E3%29%20%3D%201%20-%20%5B%5Cfrac%7Be%5E%7B-2%7D2%5E0%7D%7B01%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E1%7D%7B11%7D%2B%5Cfrac%7Be%5E%7B-2%7D2%5E2%7D%7B21%7D%2B%5Cfrac%7Be%5E%7B-3%7D2%5E3%7D%7B31%7D%5D)
P(x>3) = 1- [0.1353(1+2+2+1.33)]
P(x>3) = 1-0.856
P(x>3) = 0.1431
Als n=30, expected number is
E(x) =30*P(x>3)
E(x) = 30*0.1431
E(x) = 4.293
I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships
Perimeter of a square = 4s
Required perimeter =