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agasfer [191]
2 years ago
14

Dihybrid crosses

Biology
1 answer:
Darina [25.2K]2 years ago
8 0

Explanation:

The phenotypes and genotypes of the progeny can be determined by a dihybrid cross of the parents.

The heterozygous male will have the genotype 'SSww' and the heterozygous female will have the genotype 'ssWW'.

When crossed, the F1 offsprings will have a hybrid genotype of 'SsWw'. These offsprings are heterozygous with spotted skin and wooly hair.

On self-crossing of the F1 hybrids, we find four different combinations of the alleles- SW, Sw, SW and sw. The probability of getting each of these combinations is 1/4.

Hence, the probability of any dihybrid type is 1 out of the 16 possible genotypes. Using Punnet square, we find

9 SSWW: 3 SSww: 3 ssWW : 1 ssww

This is the phenotypic ratio of the offsprings.

The ratio of the possible genotypes will be 1:2:1:2:4:2:1:2:1.

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