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Virty [35]
2 years ago
9

What is the slope of a line that is perpendicular to the line y = 8x + 5?

Mathematics
1 answer:
Pavel [41]2 years ago
8 0

The slope of a line that is perpendicular to the line y = 8x + 5 will be -1/8.

<h3>What is the slope of perpendicular lines?</h3>

Suppose that first straight line has slope 's'

Let another straight line be perpendicular to this first line.

Let its slope be 'a'

Then due to them being perpendicular, they have their slopes' multiplication as -1

or

s x a = -1

s = -1/ a

Slope of line y = 8x + 5

s = 8

The slope of a line that is perpendicular to the line y = 8x + 5

8 x a = -1

a = -1/8

Thus, the slope is -1/8.

Learn more about slope here:

brainly.com/question/2503591

#SPJ1

You might be interested in
Which of the functions graphed below is continuous?
vaieri [72.5K]

Answer:

The answer is the second one

5 0
3 years ago
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
Ruth wants to purchase a new video game that costs $59.00 and several bags of chips that sell for $1.99 each. She can spend no m
allsm [11]

Answer:

1.99c + 59 ≥ 75, where c ≥ 8.04

Step-by-step explanation:

8 0
2 years ago
In the triangle below, which equation can<br> be used to solve for x?
aivan3 [116]
The answer is B x=13sin75/sin50
4 0
2 years ago
The surface of a table to be built will be in the shape shown below. The distance from the center of the shape to the center of
velikii [3]

A) Add three <em>line</em> segments (AD, CF, BE) to the <em>regular</em> hexagon.

B) The area of each triangle of the <em>regular</em> hexagon is 35.1 in².

C) The area of the <em>regular</em> hexagon is 210.6 in².

<h3>How to calculate the area of a regular hexagon</h3>

In geometry, regular hexagons are formed by six <em>regular</em> triangles with a common vertex. We decompose the hexagon in six <em>equilateral</em> triangles by adding three <em>line</em> segments (AD, CF, BE).The area of each triangle is found by the following equation:

A = 0.5 ·  (9 in) · (7.8 in)

A = 35.1 in²

And the area of the <em>regular</em> polygon is six times the former result, that is, 210.6 square inches.

To learn more on polygons: brainly.com/question/17756657

#SPJ1

5 0
1 year ago
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