Answer:
![\sqrt[8]x = x^\frac{1}{6}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5Dx%20%3D%20x%5E%5Cfrac%7B1%7D%7B6%7D)
Step-by-step explanation:
Given:
![\sqrt[6] x](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%20x)
Required
Represent as an exponent
In indices, we have:
![\sqrt[n]x = x^\frac{1}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5Dx%20%3D%20x%5E%5Cfrac%7B1%7D%7Bn%7D)
By comparison:
![\sqrt[8]x = \sqrt[n]x](https://tex.z-dn.net/?f=%5Csqrt%5B8%5Dx%20%3D%20%5Csqrt%5Bn%5Dx)

Apply this law to the given expression:
We have:
![\sqrt[8]x = x^\frac{1}{6}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5Dx%20%3D%20x%5E%5Cfrac%7B1%7D%7B6%7D)
Answer:
I think your answer is(C) rotation.
For this case we must represent the following expression algebraically, in addition to indicating its result:
"2 plus 9"
So, we have:

By law of the signs of the sum, we have that equal signs are added and the same sign is placed:

ANswer:
11
5×135? Distributive Property? 135 rounds to 100 and 200 5×1=5 5 and add 00 is 500 5×2=10 10 and add two 00's is 1000 the answer is in between 500 and 1000