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postnew [5]
3 years ago
11

In ΔABC, ∠CAD = 22° and segment CB = 15 cm. If the cos of 22° = 0.9272, then the sin of ∠C = _______.

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

Option B. 0.9272

Step-by-step explanation:

In the given triangle ABC, ∠CAD = 22° segment CB = 15 cm.

We have to find sin of ∠C.

In the given triangle ADC,

∠CAD + ∠ADC + ∠DCA = 180

22° + 90° + ∠DCA = 180

∠DCA = 180 - 112 = 68°

Now we have to get the value of sinC or sin of angle DCA

Therefore sinC = sin 68° = 0.9272

Option B. 0.9272 is the correct option.

rusak2 [61]3 years ago
3 0
Your answer is B. 0.9272. Hope I was able to help!
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