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Elena L [17]
2 years ago
11

En una tienda se fabrican dos tipos de mesas, de 3 y 4 patas. En total se tienen 89 mesas para vender. Se sabe que el quíntuple

de las mesas de 3 patas más la cantidad de mesas de 4 patas es igual a 277. ¿ Cuántas mesas de 3 patas se tienen para vender?
Mathematics
1 answer:
guapka [62]2 years ago
3 0

En una tienda se fabrican

La cantidad de mesas de 3 patas que tiene para la venta la tienda que las

fabrica es: 47

¿Qué es un sistema de ecuaciones?

Es un arreglo de ecuaciones que se caracteriza por tener el mismo número de incógnitas que de ecuaciones.

Existen diferentes métodos para su resolución:

Sustitución: se despeja de una ecuación una variable, quedando en función de otra para luego sustituirla en otra ecuación y así obtener

Igualación: se despeja la misma variable en dos de las ecuaciones y se igualan los resultados.

Eliminación: se resta o suman dos ecuaciones para que quede un resultado en función una variable y así despejarla.

Gráfico: se grafican las rectas y el punto de intersección es la solución del sistema.

¿Cuántas mesas de 3 patas se tienen para vender?

Definir;

x: mesas de 3 patas

y: mesas de 4 patas

Ecuaciones

x + y = 89

5x + y = 277

Aplicar método de eliminación;

Restar 1 - 2;

x + y = 89

-5x - y = -277

-4x + 0 = -188

Despejar x;

x = 188/4

x = 47

Sustituir;

47 + y = 89

Despejar y;

y = 89 - 47

y = 42

Learn more about En una tienda se fabrican here brainly.com/question/27973753

#SPJ10

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Answer :

Depends on the rate compound interest is accrued. See answers.

Step-by-step explanation:

We need the compound interest formula which is:

A = P (1+\frac{r}{n} )^{nt}

A =  final amount

P =  initial principal balance

r =  interest rate

n =  number of times interest applied per time period

t =  number of time periods elapsed

It doesn't say how frequently the interest is compounded, so we will do monthly, quarterly, and yearly.

MONTHLY

So we know the car costs $25,480 and he made a down payment of $10,000. By subtracting the down payment from the purchase price we find the loan amount.

$25,480 - $10,000 = $15,480

P = 15,480

r = 4.75% = .0475

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t = 2  

Plug everything into the compound interest formula.

A = P (1+\frac{r}{n} )^{nt}

A = 15480(1+\frac{.0475}{12})^{12*2}

A = 15480(1+\frac{.0475}{12})^{24}

A = 15480(1+.00396)^{24}

A = 15480(1.00396)^{24}

A = 15480*1.0992

A = $17016.14

Mr. Lee paid $17,016.14 when the bill came due at 2 years with interest compounded monthly.

QUARTERLY

P = 15,480

r = 4.75% = .0475

n = 4  (4 quarters in a year)

t = 2  

A = P (1+\frac{r}{n} )^{nt}

A = 15480(1+\frac{.0475}{4})^{4*2}

A = 15480(1+\frac{.0475}{4})^{8}

A = 15480(1+.0119})^{8}

A = 15480(1.0119)^{8}

A = 15480*1.099

A = 15480(1.099)

A = 17013.20

Mr. Lee paid $17,013.20 when the bill came due at 2 years with interest compounded quarterly.

YEARLY

P = 15,480

r = 4.75% = .0475

n = 1  

t = 2  

A = P (1+\frac{r}{n} )^{nt}

A = 15480(1+\frac{.0475}{1})^{1*2}

A = 15480(1+\frac{.0475}{12})^{2}

A = 15480(1+.0475})^{2}

A = 15480(1.0475)^{2}

A = 15480*1.0973

A = 16985.53

Mr. Lee paid $16,985.53  when the bill came due at 2 years with interest compounded yearly.

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