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2 years ago

Help please this is khan academy

Mathematics

1 answer:

IRISSAK [1]2 years ago

6 0

Answer:

9800 cm^2

Step-by-step explanation:

The area of a square is just the length of one of the sides squared. In the first image it's given that one of the sides is 70 cm and the shape is also a square pyramid so the base is going to be a square. So the area the base is (70 cm) ^ 2 = 4,900 cm^2. The area of a triangle is 1/2 bh. The base is given in the first image which is 70 cm and the height is also given which is 140 cm. This gives you the equation 0.5 * 140 cm * 70 cm = 4900 cm^2. Adding these two values gives you 9800 cm^2

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Algebra help? 2 questions will give brainliest!!

galina1969 [7]

1) x + 3.2= -3.5
subtract 3.2 from both sides
x+ 3.2 - 3.2= -3.5 - 3.2
it cancels out on the left
x= -6.7

2) 8/9x= 32
divide both sides by 8/9
8/9x ÷ 8/9= 32 ÷ 8/9
it cancels out on the left

to divide on the right, multiply fraction by its reciprocal/inverse

x= 32 * 9/8
multiply numerators (top)

x= (32*9)/8
x= 288/8
x= 36

ANSWER: 1) x= -6.7; 2) x= 36

Hope this helps! :)

5 0

3 years ago

For every five flowers, there are 10 yellow flowers. There are a total of 75 yellow and red flowers in her garden how many red f

umka21 [38]

Answer:

Yellow: 50

Red: 25

Step-by-step explanation:

5:10

5 times 5 = 25

10 times 5 = 50

4 0

3 years ago

Nancy invested $6000 in a bond at a yearly rate of 3%. She earned $450 interest. How long was the money invested?

4vir4ik [10]

Part 1 :
She invested $6000 in a bond. (So She Has $6000) , at a yearly rate of 3% ,

Part 2 :
She earned $450 in Interest. How long was the money invested?

At a yearly rate of 3% She earned $450. What Sum/Total/addition/and division problem add these to ratio's up?

It should come to about a 2 year Savings account , for interest.

Dose this help?

3 0

3 years ago

Example 3 find the local maximum and minimum values and saddle points of f(x, y) = x4 + y4 − 4xy + 1. solution we first locate t

allsm [11]

$f(x,y)=x^4+y^4-4xy+1$

$\begin{cases}f_x=4x^3-4y\\f_y=4y^3-4x\end{cases}$

We have critical points whenever both partial derivatives vanish:

$4x^3-4y=0\implies x^3=y\implies x=y^{1/3}$
$4y^3-4x=0\implies y^3=x=y^{1/3}\implies y^6=y\implies y=0,y=-1,y=1$
$\begin{cases}y=0\implies x=0\\y=-1\implies x=-1\\y=1\implies x=1\end{cases}$

The Hessian is

$\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}12x^2&-4\\-4&12y^2\end{bmatrix}$
$\det\mathbf H(x,y)=(12xy)^2-16$

At (0,0), we have $\det\mathbf H(0,0)=-16$ , so (0,0) is a saddle point.

At (-1, -1), we have $\det\mathbf H(-1,-1)=128>0$ and $f_{xx}(-1,-1)=12>0$ , so (-1, -1) is a local minimum.

At (1, 1), we have $\det\mathbf H(1,1)=128>0$ and $f_{xx}(1,1)=12>0$ , so (1, 1) is also a local minimum.

3 0

3 years ago

Solve for x. 2x/3 + 1 = 3 x = 1 x = 6 x = 3 x = 2

snow_tiger [21]

Answer:

your answer is x = 3

8 0

4 years ago