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Alenkinab [10]
2 years ago
11

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
fgiga [73]2 years ago
7 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\texttt{  \:The absolute maxima of f is f(-8) =  6}

____________________________________

\large \tt Solution  \: :

Absolute maxima is the maximum possible value for a given x, of a function.

and here, the maximum value is at -8, and the maximum value is 6.

\qquad \tt \rightarrow \: maximum    -   \:  \: f( - 8) = 6

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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I need help finding the factor!<br> please
irina1246 [14]

Answer:

(x-8) (x-4)

Step-by-step explanation:

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What two numbers multiply to 32 and add to -12

-8*-4 = 32

-8-4 = -12

(x-8) (x-4)

5 0
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Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo
Likurg_2 [28]

Answer:

The given equation is

25x^{2} +4y^{2}=100

Which represents an elipse.

To find its elements, we need to divide the equation by 100

\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1

Where a^{2} =25 and b^{2}=4. Remember that the greatest denominator is a, and the least is b. So, we extract the square root on each equation.

a=5 and b=2.

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is 2a=2(5)=10.

The length of the minor axis is 2b=2(2)=4.

The vertices are (0,5);(0,-5) and (2,0);(-2,0).

Now, the main parameters of an elipse are related by

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c=\sqrt{a^{2}-b^{2} }=\sqrt{25-4}=\sqrt{21}

So, the coordinates of each focus are (0,\sqrt{21}) and (0,-\sqrt{21})

The eccentricity of a elipse is defined

e=\frac{c}{a}=\frac{\sqrt{21} }{5}  \approx 0.92

The latus rectum is defined

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Finally, the graph of the elipse is attached.

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3 years ago
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Ksivusya [100]

Answer:OC

Step-by-step explanation:

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3 years ago
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Alexus [3.1K]
K + 77 = 2k - (16 - 89)
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k = 4
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