Hmm

let's try some numbers

we have 3 scenarios
x>y
x=y
x<y

x>y
x=-1 and y=-2
x-y=-1-(-2)=-1+2=1
it's positive when x>y

x=y
x=-1, y=-1
-1-(-1)=-1+1=0
nope

x<y
x=-2 and y=-1
-2-(-1)=-2+1=-1
nope

x-y is positive when 0>x>y

4 0

2 years ago

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A pet store has 11 puppies, including 2 poodles, 4 terriers, and 5 retrievers. If Rebecka and Aaron, in that order, each se

kykrilka [37]

Answer: $10/91$

Step-by-step explanation:

Since there are 14 puppies total and 5 of them are poodles, there 5 chances out of 14 for Rebecka to choose a poodle. Since the choices are done without replacement, there are now 13 left and 4 possibilities from which Aaron to choose. Since we want to calculate the probability that BOTH of them choose a poodle, we use the multiplication rule which tells us to multiply the individual probabilities.

$(5/14)(4/13) = 10/91$

4 0

2 years ago

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