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LekaFEV [45]
2 years ago
9

Every weekend me and my brother and my cousin go outside to play basketball and when i was the one who will shoot the ball to th

e ring i used the things i learned in math so I use SOH-CAH-TOA in measuring it. I want to measure the distance between me and the basketball ring. Supposed the height of the ring is 8ft from the ground and the distance between me and the basketball ring horizontally is 11.5 ft, and the angle of elevation from the ground is 50 degrees, now what is the distance of me and the ring?
Let x be the distance between me and the ring

need urgent answers with equation
by using SOH from SOHCAHTOA

Mathematics
2 answers:
Damm [24]2 years ago
8 0

Answer:

10.433cm

Step-by-step explanation:

Using SOH from TOACAHSOH,

sin50deg =  \frac{opposite}{hypotenuse}

From here we know there the opposite is 8ft (height of the ring) and hypotenuse is what we want to find, distance between you and the ring.

sin(50) =  \frac{8}{x}  \\ x \sin(50) = 8 \\ x =  \frac{8}{ \sin(50) }   \\ x = 10.443cm(rounded \: to \: 5sf)

Rus_ich [418]2 years ago
6 0

Answer:

10 . 44 ft

Step-by-step explanation:

sin 50 = opposite leg / hypotenuse = 8 / x

8 / sin 50 = x    = 10 .44  ft

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<span>How the value of 8 in 880 related
=> 880 = 8 hundreds 8 tens
=> This given number is a whole numbers, thus the value of 8 in the hundreds place is ten times larger than the 8 In the tens place. How?
Try multiplying 8 tens by 10
=> 8 tens = 80
=> 80 x 10
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When 80 is multiplied by ten the answer is 800 and when 800 is divided by 10 the answer is 80.
That concludes that there’s 10 times difference between the two 8s in the given number.</span><span>


</span>



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