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suter [353]
3 years ago
14

An urn contains 78 slips of paper. Each slip bears a number from 1 to 26. Each number appears on 3 different slips. A child sele

cts two slips of paper at random and without replacement. Find the probability that the drawn slips have the same number. Write your answer as a reduced fraction.
Mathematics
1 answer:
Alina [70]3 years ago
3 0

Answer:

2 / 77

Step-by-step explanation:

Each number appears 3 times in the urn.

After picking any number, the number picked will appear only two more times in the urn, and the total slips of paper will be 77.

So for any first number we pick, the probability of the second number picked being the same number as the first pick is the number of times the same number appears in the urn (2) over the total number of slips in the urn (77):

Probability = 2 / 77

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3 years ago
a jewelry store buys 24 necklaces for $300. the store wants to make a profit of $540. assuming it sells all 24 necklaces, how mu
Serga [27]
If its meaning making a profit after the $300 then:
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9514 1404 393

Answer:

  B, C

Step-by-step explanation:

The sums are ...

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  B) 118.16

  C) 18.97

  D) 27.76

Sums B and C have 8 in the ones place.

__

You can add the ones-place digits. If the resulting ones-digit is 7 or 8, then add the tenths-place digits. If the carry from that sum, added to the sum of ones-place digits, gives a value of 8 or 18, then you found a sum with a ones digit of 8.

6 0
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Lis 10 múltiples of 8
andrey2020 [161]
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Read 2 more answers
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