Question

@###GEOMETRY, SEE PHOTO! PLEASE HELP ASAP!####@

Answer 1

Since this is a right triangle, we can use our trigonometric functions to solve for x.

Since we know the adjacent side and hypotenuse, we will use cosine.

Based on the function $\cos(x) = \frac{adj}{hyp}$, we can solve for x. The adjacent side is 7 and the hypotenuse is 12. Plugging this in, we get $\cos(x) = \frac{7}{12}$.

Now, we must use our inverse trigonometric functions to solve for x:
$\cos^{-1}(\cos(x)) = \cos^{-1}(\frac{7}{12})$

The inverse cosine and cosine on the left side cancel, leaving you with:
$x = \cos^{-1}(\frac{7}{12}) = \boxed{54.3^{\circ}}$