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4 years ago

Can someone answer this real quick please

Mathematics

2 answers:

Veronika [31]4 years ago

8 0

Polynomial C or Answer C

Marta_Voda [28]4 years ago

6 0

Answer: Polynomial C

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A binomial is a polynomial with two terms. A term can be a single number/variable or numbers and variables multiplied together, and are separated by + or -.

Looking at your list, you can already eliminate A and B because they both have three terms.

A 5th degree polynomial has the highest power of the variable as raised to the 5th power.

Between C and D, only choice C has x raised to the 5th power.

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The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t

yulyashka [42]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 0.5 \ in$

Generally the Null hypothesis is $H_o : \mu = 0. 5 \ in$

The Alternative hypothesis is $H_a : \mu \ne 0.5 \ in$

Considering the parameter given for part a

The sample size is n = 15

The test statistics is t = 1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145$

We are making use of this $t_{\frac{\alpha }{2} }$ because it is a one-tail test

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that $t < t_{\frac{\alpha }{2} }$ so the null hypothesis would not be rejected

Considering the parameter given for part b

The sample size is n = 15

The test statistics is t = -1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145$

Looking at the value of t and $t_{\frac{\alpha}{2} ,df }$ the we see that t does not lie in the area covered by $t_{\frac{\alpha}{2} , df }$ (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part c

The sample size is n = 26

The test statistics is t = -2.55

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787$

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that t does not lie in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part d

The sample size is n = 26

The test statistics is t = -3.95

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787$

Looking at the value of t and $t_{\frac{\alpha}{2} }$ the we see that t lies in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis

6 0

3 years ago

37546 rounded to nearest 10

lorasvet [3.4K]

Nearest ten would be the 4. And because the number to the left is bigger then 5 your round it. Therefore your answer is 50.

7 0

3 years ago

Read 2 more answers

5. Which of the following graphs shows the solution set to 4x – 5 ≥ 3 or 5 – x > 8?

Nastasia [14]

Second option

Also, the reason it can not be the third one is because the circle at -3 is shaded in, meaning x can equal - 3, whereas its not present in this inequality: 5 – x > 8

5 - x = 8

5 = x + 8

-8

-3 = x

(when solving for x, make sure its positive, that's why I started of by adding x on both sides. It makes it easier to figure out the values that works of x. )

Hope this helps!

8 0

2 years ago

Wetlands offer a diversity of benefits. They provide a habitat for wildlife, spawning grounds for U.S. commercial fish, and rene

mrs_skeptik [129]

Question Completion:

How are the percentages distributed? Is the distribution skewed? Are there any gaps? (Select all that apply.)

Answer:

1. The percentages are concentrated from 20% to 60%.

2. These data are strongly skewed left.

3. There are no gaps in the data.

Step-by-step explanation:

1. Data

Percentage loss of wetlands per state

46 37 36 42 81 20 73 59 35 50

87 52 24 27 38 56 39 74 56 31

27 91 46 9 54 52 30 33 28 35

35 23 90 72 85 42 59 50 49

48 38 60 46 87 50 89 49 67

2. Re-arrangement of

Percentage loss of wetlands per state (in ascending order)

9 20 23 24 27 27 28 30

31 33 35 35 35 36 37 38

38 39 42 42 46 46 46 48

49 49 50 50 50 52 52 54

56 56 59 59 60 67 72 73

74 81 85 87 87 89 90 91

5 0

3 years ago

A $1 lottery ticket offers a grand prize of $18000; 10 runner-up prizes each pay $1800; 100 third-place prizes each pay $180; an

weeeeeb [17]

Answer:

I answer u after my online class

7 0

3 years ago