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Viefleur [7K]
2 years ago
14

Lenny bought x shares of stock for Sy per share last month. He paid

Mathematics
1 answer:
gulaghasi [49]2 years ago
8 0

Lenny's net proceeds algebraically are found as;\rm |xy + 20 -  \frac{98}{100} |

<h3>What is the equation?</h3>

A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

Let the bought share will be $ x, and $y is the price per share

Paid fees to the broker = $ 20

The total amount spent = $(xy+20)

The price at which each share sells = $ A

Broker commission = 2 %

The total amount obtained after selling the shares;

⇒ ax - 2% of ax

⇒ 98 % of ax

Hence, Lenny's net proceeds algebraically are found as;\rm |xy + 20 -  \frac{98}{100} |

To learn more, about equations, refer;

brainly.com/question/10413253

#SPJ1

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Step-by-step explanation:

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2) Multiplication

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Answer:

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Step-by-step explanation:

x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad  x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}

y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9

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3 years ago
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