Answer:
15
Step-by-step explanation:
Answer:
Length of longer length=132 inches
Length of shorter length=33 inches
Step-by-step explanation:
Step 1: Determine total length of pipe
Total length of pipe=165 inches
Step 2: Derive expression for all the lengths
We can express all these lengths as follows;
L=l1+l2
where;
L=total length
l1=length of longer piece
l2=length of shorter piece
but;
length of longer piece=4×length of shorter piece
replacing;
l1=4l2
replacing;
L=165
l1=4×l2
165=l 2+4 l2
5 l2=165
l2=165/5
l2=33 inches
l1=length of longer length=33×4=132 inches
l2=length of shorter length=33 inches
Answer:
x = 32
m∠7 = 94
m∠8 = 86
m∠3 = 94
Step-by-step explanation:
(2x + 30) + (3x - 10) = 180
5x + 20 = 180
5x = 160
x = 32
m∠7 = 2(32) + 30 = 94
m∠8 = 3(32) - 10 = 86
<u>or</u>
m∠8 = 180 - 94 = 86
<u>m∠3 ≈ m∠7</u> (corresponding angles)
If you evaluate directly this function at x=0, you'll see that you have a zero denominator.
Nevertheless, the only way for a fraction to equal zero is to have a zero numerator, i.e.

So, this function can't have zeroes, because the only point that would annihilate the numerator would annihilate the denominator as well.
Moreover, we have

So, we can't even extend with continuity this function in such a way that 
X is greater than or equal to -9.