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const2013 [10]
2 years ago
12

Find the measure of x.

Mathematics
2 answers:
san4es73 [151]2 years ago
5 0

Answer:

cosx=adjacent/hypotenuse

triangle angle =180-(90+38)

=52°

cos(52°)=16/x

x=16/cos52

x≈23.373

BARSIC [14]2 years ago
3 0

Answer:

25.99

Step-by-step explanation:

SOH CAH TOA

(sin = opposite / hypotenuse

cos = adjacent / hypotenuse

tan = opposite / adjacent)

For the angle measurement provided (38 degrees), we know the opposite leg value, and we need to find the hypotenuse

the measurement of sin (opposite / hypotenuse) relates these two measurements

we can plug in our known values into sin:

sin = opposite / hypotenuse

sin (38) = 16 / x

(note: sin 38 = 0.61566147532, which we can round to 0.61566)

0.61566 = 16 / x

· x                   ·x           {multiply both sides by x to get rid of fraction}

0.61566(x) = 16

÷ 0.61566       ÷0.61566     {divide both sides by 0.61566 to isolate 1x}

x = 25.9883702043

{round to nearest hundredth}

x = 25.99

so, the measure of x is 25.99  {rounded to the nearest hundredth}

hope this helps!! have a lovely day :)

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zlopas [31]

The values are a = 7, b = -9, c = -18.

<u>Step-by-step explanation:</u>

The given quadratic equation is 7x^{2} - 9x = 18

The general form of the quadratic equation is ax^{2} + bx + c = 0

where,

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.

So, bring the constant term 18 to the left side of the equation for equating it to zero.

⇒ 7x^{2} - 9x - 18 = 0

Compare the above equation with general form ax^{2} + bx + c = 0

⇒ a = 7

⇒ b = -9

⇒ c = -18

Therefore, the values of a, b, and c are 7, -9 and -18.

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4 years ago
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If b√2 = 6, what does b equal? I don't know why I'm stuck on this problem, but could somebody help me?
kotegsom [21]

Answer:

Step-by-step explanation:

Divide both sides by the square root of 2. If you are looking for an exact answer that is rationalized, it would be found by multiplying 6/sqrt(2) * sqrt(2)/sqrt(2) to get

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The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

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13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

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P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

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A pile of 55 coins, consisting of nickels and dimes, is worth $3.90. find the number of each.
Lady_Fox [76]
Answer is: 32 nickels and 23 dimes.
<span>x - number of nickels .
y -number of dimes.
two equations in two unknowns:
1) x + y = 55
2) 0,05x + 0,1y = 3,90.
</span>nickel is a five-cent coin.
dime is a ten-cent coin.<span>
solve equation 1) for x and substitute for x in equation 2)
x = 55 - y
0,05</span>·(55 - y) + 0,1y = 3,90<span>2,75 - 0,05y + 0,1y = 3,90
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noname [10]

Its is true that C ⊆ D means Every element of C is present in D

According to he question,

Let C = {n ∈ Z | n = 6r – 5 for some integer r}

D = {m ∈ Z | m = 3s + 1 for some integer s}

We have to prove : C ⊆ D

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Using distributive property,

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Let s = 2r - 2

Then, m = 3r + 1 with r some integer and thus m ∈ D

Since , every element of C is also an element of D

Hence ,  C ⊆ D proved !

Similarly, you have to prove D ⊆ C

To know more about integers here

brainly.com/question/15276410

#SPJ4

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