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tamaranim1 [39]

2 years ago

9

Jamie is looking for the rate and unit rate of the following ratio below.

1 answer:

bezimeni [28]2 years ago

3 0

Answer: in explanation

Step-by-step explanation:

Rate is simplest form, so 3 napkins for 5 cents.

Unit rate is for 1 x value, so 1 napkin for 0,6 cents.

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What is 12 X -19 equals 5X -5

Anettt [7]

Answer:

Step-by-step explanation:12x=5x+14, 7x=14,

x=2

5 0

3 years ago

A boat travels 33 miles downstream in 4 hours. The return trip takes the boat 7 hours. Find the speed of the boat in still water

Paha777 [63]

<u>Answer:</u>

Speed of the boat in still water = 6.125 miles/hour

<u>Step-by-step explanation:</u>

We are given that a boat travels 33 miles downstream in 4 hours and the return trip takes the boat 7 hours.

We are to find the speed of the boat in the still water.

Assuming $S_b$ to be the speed of the boat in still water and $S_w$ to be the speed of the water.

The speeds of the boat add up when the boat and water travel in the same direction.

$Speed = \frac{distance}{time}$

$S_b+S_w=\frac{d}{t_1}=\frac{33 miles}{4 hours}$

And the speed of the water is subtracted from the speed of the boat when the boat is moving upstream.

$S_b-S_w=\frac{d}{t_2}=\frac{33 miles}{7 hours}$

Adding the two equations to get:

$S_b+S_w=\frac{d}{t_1}$

+ $S_b-S_w=\frac{d}{t_2}$

___________________________

$2S_b=\frac{d}{t_1} +\frac{d}{t_2}$

Solving this equation for $S_b$ and substituting the given values for $d,t_1, t_2$ :

$S_b=\frac{(t_1+t_2)d}{2t_1t_2}$

$S_b=\frac{(4 hour + 7hour)33 mi}{2(4hour)(7hour)}$

$S_b=\frac{(11 hour)(33mi)}{56hour^2}$

$S_b=6.125 mi/hr$

Therefore, the speed of the boat in still water is 6.125 miles/hour.

6 0

3 years ago

Read 2 more answers

A square has an area of 81 cm.(squared)What is the length of each side?

Andrej [43]

Answer:

9

Step-by-step explanation:

6 0

3 years ago

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If f(x)=x^2+3x+4 which of the number choices represents (f(x+h)-f(x))/h?

Helen [10]

In case you're not already aware, the expression $\frac{f(x+h)-f(x)}h$ is called the "difference quotient" and represents the average rate of change of a function $f$ over an interval $[x,x+h]$ .

For the function $f(x)=x^2+3x+4$ , by substituting $x+h$ we get

$f(x+h)=(x+h)^2+3(x+h)+4=(x^2+2xh+h^2)+(3x+3h)+4=x^2+3x+4+(2x+3)h+h^2$

Then the difference quotient is

$\dfrac{f(x+h)-f(x)}h=\dfrac{(x^2+3x+4+(2x+3)h+h^2)-(x^2+3x+4)}h$

$=\dfrac{(2x+3)h+h^2}h=2x+3+h$

where the last equality holds as long as $h\neq0$ .

5 0

3 years ago

1) What is the ratio of out-of-state fans attending the game to local fans?

arsen [322]

Answer:

b

Step-by-step explanation:

4 0

2 years ago