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Furkat [3]
2 years ago
11

Lol please help me goodness gracious

Mathematics
1 answer:
PIT_PIT [208]2 years ago
5 0

To find x = \frac{1}{2} (AB+CD)

x=\frac{1}{2} (46+25)\\\ x=\frac{1}{2} (71)\\ x =35.5

Hope it helps!

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Would really appreciate it... will mark brainliest
d1i1m1o1n [39]

Exponential growth would include, A = 20,000(1.08)^t, A=40(30), P=1700(1.07).

Decay would include, A=80(1/2)^t, A= 1600(.8), P=1700(.93)

Hope this helps.

5 0
3 years ago
Read 2 more answers
Solve the conjunction and describe the solution set.
BaLLatris [955]
 -5 ≤ 3m + 1 < 4
- 1           - 1  - 1
 -6 ≤ 3m < 3
  3      3     3
 -2 ≤ m < 1

Solution Set: {m|-2 ≤ m < 1}, {m|m ≥ -2 and m < 1}, [-2, 1)

The answer is A.
7 0
3 years ago
The subject of the formula below is y.<br>a=4x/t - p<br>Rearrange the f make x the subject.​
Crazy boy [7]

Answer:

x = t(a+p)/4

Step-by-step explanation

Given the expression

​a=4x/t - p

We are to make x the subject of the formula

a=4x/t - p

Add p to both sides

a+p = 4x/t - p+p

a+p = 4x/t

Cross multiply

t(a+p) = 4x

Rearrange

4x = t(a+p)

Divide both sides by 4

4x/4 = t(a+p)/4

x = t(a+p)/4

4 0
3 years ago
Help please!! really quickly
yKpoI14uk [10]

y =  \frac{7}{5} x + 1
8 0
3 years ago
The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.
emmasim [6.3K]

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

or,\frac{30 {xy + 20xy}^{2} }{10xy}  = l \\

or, \: l = 3 {x}^{2 - 1}  + 2cm

\boxed{\sf{l = (3x+2)cm}}

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

= \frac{20 {x}^{4} {y}^{2}  }{5 {x}^{3} y}   \\

= 4xy

The product of 3x and 4y = 6xy

= 6x - 4xy

= \boxed{\sf {2xy}}

hope it helped !!!!

7 0
2 years ago
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