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2 years ago

Lol please help me goodness gracious

Mathematics

1 answer:

PIT_PIT [208]2 years ago

5 0

To find x = $\frac{1}{2} (AB+CD)$

$x=\frac{1}{2} (46+25)\\\ x=\frac{1}{2} (71)\\ x =35.5$

Hope it helps!

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What is the difference between 179 and 320

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3 years ago

This isn't something specific I need to know for school, I'm just curious. I know the most commonly used variables are x, y, and

andre [41]

Answer:

Any letter you want

Step-by-step explanation:

The letters used for variables don't matter. What matters is what the variables represent: their numerical value. Variables are just to help identify what needs solving. Other common variables are a, b, and c which are found frequently in trigonometry. To answer your question, there are no "next letters." You can use any letter you'd like as a variable because it holds the same numerical value. Basically, the whole alphabet is at your disposal.

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3 years ago

twice the smaller of two consecutive integers increased by the larger integer is at least 25. what is the number?

stira [4]

$x,x+1-\ two \ consecutive\ numbers\\\\
2x+x+1\geq25\\\\
3x+1\geq25\ \ \ | subtract\ 1\\\\
3x\geq24\ \ \ | divide\ by\ 3\\\\
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3 0

3 years ago

Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. What is the

vodomira [7]

Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. The rate of change is 391.5 % increase

<em><u>Solution:</u></em>

Given that Two years ago, Sally had 5,000 dogs in her dog shelter

Now she has 24,575 dogs

To find: rate of change

A rate of change is a rate that describes how one quantity changes in relation to another quantity

<h3><u>Steps to follow:</u></h3>

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number.

Then: divide the increase by the original number and multiply the answer by 100.

% change = Increase ÷ Original Number x 100

$\text {rate of change }=\frac{\text { new value }-\text {original value}}{\text {original value}} \times 100$

$\begin{array}{l}{\text { rate of change }=\frac{24,575-5000}{5000} \times 100} \\\\ {\text { rate of change }=\frac{19575}{5000} \times 100=391.5}\end{array}$

Thus the rate of change is 391.5 % increase

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3 years ago