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Romashka-Z-Leto [24]
3 years ago
12

Slope of y= 4x - 1.

Mathematics
1 answer:
love history [14]3 years ago
8 0

Answer:

Slope <em>m</em> = 4

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

[Slope-Intercept] y = 4x - 1

<u>Step 2: Break Function</u>

<em>Identify Parts.</em>

Slope <em>m</em> = 4

y-intercept <em>b</em> = -1

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I am very confused with this problem please help me
Tanya [424]

Answer:

The answer is -0.5

Step-by-step explanation:

Divide both side by the numeric factor on the left side then solve

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Which proportion can be used to solve for f in the figure above?
kirill [66]

Answer:

You could use the Pythagnerum Theorem

Step-by-step explanation:

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2 years ago
Pilar says that two linear systems below have the same solution. (see picture) Is she correct? Explain.
wariber [46]
The first set:

3x + 2y = 2  ---1)
5x + 4y = 6  ---2)

From 1), multiply all by 2, 6x + 4y = 4  ---3)

3) - 2),

6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2

Sub in x = 2 into 1),

3(2) + 2y = 2
2y = -4
y = -2

(2 , -2)


The second set:

3x + 2y = 2  ---1)
11x + 8y = 10  ---2)

From 1), multiply all by 4, 12x + 8y = 8 ---3)

3) - 2),

12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
x = -2

From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.

Hope this helped! Ask me if there's any working from here that you don't understand! :)

5 0
3 years ago
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find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

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2 years ago
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s344n2d4d5 [400]
The correct answer is B
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3 years ago
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