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2 years ago

The main steps of photosystem 2 include which of the following

Biology

1 answer:

Anestetic [448]2 years ago

8 0

Incomplete Question options not given

Photosystem II is the first protein complex in oxygenic photosynthesis's light-dependent processes. It is found in plants, algae, and cyanobacteria's thylakoid membrane.

The thylakoid membrane, which is a part of the chloroplast in plant cells, is where Photosystem I and Photosystem II are found.

The products of the light dependent processes are delivered to the light independent reactions as ATP and NADPH.

Water molecules are divided into oxygen atoms and hydrogen ions when photosystem II pulls replacement electrons from them.

The thylakoid compartment retains the hydrogen ions from the water.

High energy electrons are transferred from Photosystem II to Photosystem I in the electron transfer chain.

The high-energy electrons in the photosystem received energy from sunlight while they were there.

Photosystem I releases high-energy electrons into the atmosphere.

The high energy electrons join NADP+ and a hydrogen ion after going via an electron transfer chain.

ADP and Pi are combined to create ATP with the help of hydrogen ions passing via the ATP synthases.

So to conclude with we can say that the initial protein complex in the light dependent processes of oxygenic photosynthesis is called photosystem II. It may be found in plants, algae, and cyanobacteria's thylakoid membrane.

Learn more about photosystem II here:

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If:
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 $I^{B}$ - the frequency of IB allele
 $i$ - the frequency of i allele

Then:
 $I^{A} I^{A}$ + $I^{A} i$ - the frequency of individuals with A blood type
 $I^{B} I^{B}$ + $I^{B} i$ - the frequency of individuals with B blood type
 $ii$ - the frequency of individuals with O blood type

Let's first take a look on the Dunker population:
$I^{A} = 0.3$
$ii=0.16
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Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
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Now, we have the frequencies of two alleles ( $I^{A}$ and $i$ ). To calculate the frequency of $I^{B}$ allele, we will use the formula:
 $I^{A} + I^{B} + i = 1$
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⇒ $I^{B} = 1-0.3-0.4$
⇒ $I^{B} = 0.3$

Now, in the general population:
$I^{A} = 0.4$
$ii=0.25$

Similarly to the work for the Dunker population:
 $i= \sqrt{ii}$
⇒ $i = \sqrt{0.25}$
⇒ $i=0.5$

$I^{A} + I^{B} + i = 1$
⇒ $I^{B} = 1- I^{A} - i$
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