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zalisa [80]
2 years ago
11

What does AU stand for in computer?

Computers and Technology
1 answer:
SpyIntel [72]2 years ago
7 0

Answer:

AU stands for <em>Audio Units.</em>

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Opinion on sandshrew​
Alex

Answer:Sandshrew is cute

Explanation:

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Lonic compounds are also known as <br> a. salts <br> b. valence <br> c.organic <br> d.elements
shutvik [7]
I'm not quite sure but it maybe b
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Read 2 more answers
Read the two sentences below. Then select the response that best describes the verb tense used in the sentences.
N76 [4]
I would say A because it was talking about something in the present but what they were talking about was in past. so I would think A
6 0
3 years ago
Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.
arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

    public static void main(String[] args)

    {

         Scanner SC = new Scanner(System.in);

         RomantoDecimal r = new RomantoDecimal();

         System.out.println("Enter a Roman number :");

         // INPUT A ROMAN NUMBER

         String rNum = SC.next();

         // CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

         r.convertToDecimal(rNum);

    }

    // M=1000, D=500, C=100, L=50, X=10, V=5, I=1

    public void convertToDecimal(String roamNo)

    {

         int number = 0;

         // TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

         for (int i = roamNo.length() - 1; i >= 0; i--)

         {

             // FIND OUT WHETHER IT IS 'M' OR NOT

             if (roamNo.charAt(i) == 'M')

             {

                  if (i != 0)

                  { // CHECK WHETHER THERE IS C BEFORE M

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 900;

                            i--;

                            continue;

                       }

                  }

                  number = number + 1000;

             }

             // FIND OUT WHETHER IT IS 'D' OR NOT

             else if (roamNo.charAt(i) == 'D')

             {

                  if (i != 0)

                  {

                  // CHECK WHETHER THERE IS C BEFORE D

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 400;

                            i--;

                            continue;

                       }

                 }

                  number = number + 500;

             }

            // FIND OUT WHETHER IT IS 'C' OR NOT

             else if (roamNo.charAt(i) == 'C')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'X')

                       {

                            number = number + 90;

                            i--;

                            continue;

                      }

                  }

                  number = number + 100;

             }

             else if (roamNo.charAt(i) == 'L')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i) == 'X')

                       {

                            number = number + 40;

                            i--;

                            continue;

                       }

                  }

                  number = number + 50;

             }

             // FIND OUT WHETHER IT IS 'X' OR NOT

             else if (roamNo.charAt(i) == 'X')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 9;

                            i--;

                            continue;

                       }

                  }

                  number = number + 10;

             }

             // FIND OUT WHETHER IT IS 'V' OR NOT

             else if (roamNo.charAt(i) == 'V')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 4;

                            i--;

                            continue;

                       }

                  }

                  number = number + 5;

             }

            else // FIND OUT WHETHER IT IS 'I' OR NOT

             {

                  number = number + 1;

             }

         }// end for loop

         System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

    }

}

3 0
3 years ago
1.Write a Java program to solve the following problem using modularity. Write a method that rotates a one-dimensional array with
Westkost [7]

Answer:

Explanation:

The following code is written in Java and it asks the user for the size of the array. Then it randomly populates the array and prints it. Next, it rotates all the elements to the right by 1 and prints the new rotated array.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Random r = new Random();

       Scanner in = new Scanner(System.in);

       System.out.println("Enter Size of the Array: ");

       int arraySize = in.nextInt();

       ArrayList<Integer> myList = new ArrayList<>();

       for (int x = 0; x < arraySize; x++) {

           myList.add(r.nextInt(15));

       }

       System.out.println("List Before Rotation : " + Arrays.toString(myList.toArray()));

       for (int i = 0; i < 1; i++) {

           int temp = myList.get(myList.size()-1);

           for (int j = myList.size()-1; j > 0; j--) {

               myList.set(j, myList.get(j - 1));

           }

           myList.set(0, temp);

       }

       System.out.println("List After Rotation :  " + Arrays.toString(myList.toArray()));

   }

}

6 0
3 years ago
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