All categories

4 years ago

Compare the logical link control and the media access control. Which of the following is a correct statement?

Computers and Technology

2 answers:

Amanda [17]4 years ago

7 0

The answer is D. The logical link control involves pointers sending frames and waiting for responses.

Snezhnost [94]4 years ago

3 0

The answer is, the logical link control and regulates the timing of a frame's access to a part of network, the media access control ensure successful traffic between layers of the network. They are both parth of the data network layer.

You might be interested in

Exercise : Randomizer In this exercise, we are going to create a static class Randomizer that will allow users to get random int

Nutka1998 [239]

Answer:

Here the code is by using java.

Explanation:

//Randomizer.java

public class Randomizer {

public static int nextInt() {

//get random number from 1-10

int randInteger = (int) (Math.random() * (11) + 1);

//if number is greater than 10 or less than 1

while (randInteger > 10 || randInteger < 1) {

randInteger = (int) (Math.random() * (11) + 1);

}

return randInteger;

}

public static int nextInt(int min, int max) {

//formula to get random number from min-max

int randInteger = (int) (Math.random() * (max + 1) + min);

while (randInteger > max || randInteger < min) {

randInteger = (int) (Math.random() * (max + 1) + min);

}

return randInteger;

}

//RandomizerTester.java

public class RandomizerTester {

public static void main(String[] args) {

System.out.println("Results of Randommizer.nextInt()");

for (int i = 0; i < 10; i++) {

System.out.println(Randomizer.nextInt());

}

int min = 5;

int max = 10;

System.out.println("\n Results of Randomizer.nextInt(5,10)");

for (int i = 0; i < 10; i++) {

System.out.println(Randomizer.nextInt(min, max));

}

OUTPUT:

Results of Randommizer.nextInt()

Results of Randomizer.nextInt(5,10)

4 0

3 years ago

Write a program that prompts the user to enter integers in the range 1 to 50 and counts the occurrences of each integer. The pro

galben [10]

Answer:

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
int num[] = new int[51];
Scanner input = new Scanner(System.in);
System.out.print("Number of input: ");
int limit = input.nextInt();
for(int i=0; i < limit; i++){
System.out.print("Input a number (1-50): ");
int k = input.nextInt();
num[k]++;
}
for(int j=1; j < 51; j++){
if(num[j] > 0){
System.out.println("Number of occurrence of " + j + ": " + num[j]);
}
}
}
}

Explanation:

The solution is written in Java.

Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).

Create a Scanner object and get user entry the number of input (Line 6-7).

Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).

At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).

8 0

4 years ago

What are the constraints of mine shaft head gear

Serhud [2]

Answer:

Mine headgear constructions support wheel mechanisms for suspending winding cables that transport workers and ore up and down deep level shafts. These strange anthropomorphic structures have become the iconic symbol for mining.

4 0

3 years ago

Add the following methods to the ArrayCollection class, and create a test driver for each to show that they work correctly. In o

maks197457 [2]

Answer:

Attached are screenshots of the working code - baring in mind this only works on mutable Collection types. (ones that can be changed) if you use Collections that don't support this you may experience an Unsupported Operation Exception - but this is expected.

Explanation:

Using Java streams as an alternative for some answers.