The inverse of f(x)=2x-10
1 answer:
The inverse of the function f(x) = 2x - 10 is f-1(x) would be x/2 + 5.
Lets try to solve it,
We will be using the inverse function to solve this.
f(x) =
Replace f(x) with y.
Interchange x and y
Solve for y
Replace y with f-1(x).
Thus, the inverse of the function f(x) = 2x - 10 is f-1(x) = x/2 + 5
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Answer:
<em>not</em> a rectangle
Step-by-step explanation:
There are several ways to determine whether the quadrilateral is a rectangle. Computing slope is one of the more time-consuming. We can already learn that the figure is not a rectangle by seeing if the midpoint of AC is the same as that of BD. (It is not.) A+C = (-5+4, 5+2) = (-1, 7). B+D = (1-2, 8-2) = (-1, 6). (A+C)/2 ≠ (B+D)/2, so the midpoints of the diagonals are different points.
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The slope of AB is ∆y/∆x, where the ∆y is the change in y-coordinates, and ∆x is the change in x-coordinates.
... AB slope = (8-5)/(1-(-5)) = 3/6 = 1/2
The slope of AD is computed in similar fashion.
... AD slope = (-2-5)/(-2-(-5)) = -7/3
The product of these slopes is (1/2)(-7/3) = -7/6 ≠ -1. Since the product is not -1, the segments AB and AD are not perpendicular to each other. Adjacent sides of a rectangle are perpendicular, so this figure is not a rectangle.
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Our preliminary work with the diagonals showed us the figure was not a parallelogram (hence not a rectangle). For our slope calculation, we "magically" chose two sides that were not perpendicular. In fact, this choice was by "trial and error". Side BC <em>is perpendicular</em> to AB, so we needed to choose a different side to find one that wasn't. A graph of the points is informative, but we didn't start with that.
Answer: C)46 ft
Step-by-step explanation:
We know that the circumference of a circle can be calculated with this formula:
Where "r" is the radius of the circle.
Since John is putting a fence around his garden that is shaped like a half circle and a rectangle, then we can find how much fencing he needs by making this addition:
Where "l" is the lenght of the rectangle and "w" is the width of the rectangle.
Since we know that the radius of the circle is half its diameter, we can find "r". This is:
Then, substituting values (and using ), we get: