Here are the original equations:
2x + 2y = 14
x + 2y = 11
We immediately note that these two equations form a system. So, we can use substitution to solve the second equation for x. To do this, all that needs to be done is to subtract 2y from both sides, to get x = 11 - 2y. Next, we substitute the derived expression for x into the first equation to get 2(11-2y) + 2y = 14. We can use the distribute property to get 22 - 4y + 2y = 14. Then, we can combine like terms to get 22 - 2y = 14. After that, we subtract 22 from both sides to get -2y = -8. Finally, we divide -2 from both sides to get y = 4.
Now that we have the value for y, we can substitute our derived value into the second equation, since it will be much faster. After doing this, we get x + 2(4) = 11. We can simplify the left side of the equation and subtract the product from both sides, which gives us x = 4. Therefore, the answer to your query is x = 4, y = 4. Hope this helps and happy Halloween!
It is 21 g What are the benefits and what are the drawback to certifying/licensing computer/IT professionals?
In the second parenthesis is the -2 and -5 inside the house or is -5 separate
Answer:
Step-by-step explanation:
I suppose we could factor this and find out how long the ball was in the air. From there we could determine its halfway point in terms of time, and then sub that time in for t in the position function to get the height at that time. But in order to avoid that, which may actually lead to an estimation as opposed to the actual height and time, we will use calculus.
Keep in mind that the first derivative of the position function is velocity. You have learned in Physics that if an object is at the very tip-top of its travels it has 0 velocity (this is because the object HAS to stop moving in order to turn around and head the other direction). So we will simply find the function's derivative, set it equal to 0 and then solve for t. The position function is
The first derivative, aka as the velocity function, is
Setting it equal to 0:
-20 = -32t so
That is WHEN the object is at its max height. To find out what the max height it, we will sub that t value into the position function.
gives us that the ball's position at five-eighths of a second is 14.25 feet.
