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balandron [24]
2 years ago
6

An insurance policy sells for $600. Based on past data, an average of 1 in 50 policy holders

Mathematics
1 answer:
mylen [45]2 years ago
5 0

Using a discrete distribution, we have that:

a) The expected value is of $250 per policy sold.

b) The expected profit for 10,000 policies is of $2,500,000.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

Considering that an insurance profit sells for $600, the distribution of the company's earnings is given as follows:

  • P(X = -4400) = 0.02.
  • P(X = -9400) = 0.01.
  • P(X = -29400) = 0.005.
  • P(X = 600) = 0.965.

Hence the expected value for a policy sold is given by:

E(X) = 600(0.965) - 4400(0.02) -9400(0.01) - 29400(0.005) = 250.

For 10,000 policies, the expected profit is given by:

E = 10000 x 250 = 2,500,000.

More can be learned about discrete distributions at brainly.com/question/24802582

#SPJ1

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Answer:

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Step-by-step explanation:

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where

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From the question the points are

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The distance is

|AB|  =  \sqrt{ ({10 + 2})^{2} +  ({ - 1 - 5})^{2}  }  \\  =  \sqrt{ {12}^{2}  +  ({ - 6})^{2} }  \\  =  \sqrt{144 + 36}  \:  \:  \:  \:  \:  \:  \:   \\  =  \sqrt{180}  \\  = 6 \sqrt{5}  \:  \:  \\  =13.416407

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<h3>13.4 units to the nearest tenth</h3>

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