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3 years ago

12

Tara is a little worried about this breakdown because she knows the drug will likely affect younger women differently than older

women

2 answers:

Thepotemich [5.8K]3 years ago

3 0

Answer:

NOT TO WASTE POINTS BUT PLEASE DO NOT USE THAT LINK ABOVE

Step-by-step explanation:

IT TRACKS YOU

Verdich [7]3 years ago

3 0

Answer:

what kind of question is that

Step-by-step explanation:

Person above, really??

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The measure of angle A is 4 degrees greater than the measure of angle B. The two angles are complementary. Find the measure for

Elenna [48]

Sorry but i only know the answer for the 1st question.
--------------------------
If the angles are complementary they measure 90°.
1st find half of 90
which is 45.
Find 4 more than 45.
which is 49°
then subtract 90-49=41
so the measurement of the 2 angles are
49 and 41
Hope it helps!!

7 0

4 years ago

In which table does y vary directly with x?

g100num [7]

Answer:

In which table does y vary directly with x? ОА. х у 1 -2 2 -4 3 -16 ОВ. Х у 1 -5 2 18 3 41 Ос. х у 1 26 2 52 3 78 - did not match any documents.

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8 0

3 years ago

Who can help me d e f thanks

12345 [234]

d)

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

e)

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

f)

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

Where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i

xz_007 [3.2K]

Vertically in the middle

8 0

3 years ago

Heidi, a jewelry salesperson, earns a commission of $55 every time she sells a diamond ring. How many rings does she have to sel

Rashid [163]

Hi Alyssasmith21!
So $55 for each diamond ring and wants to know how many she needs to sell to get $605. OK this is easy what we have to do is 605/55 to find how many rings which is 11. She needs to sell 11 rings to get $605.
Hope this helps!

3 0

3 years ago