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LiRa [457]
2 years ago
15

The two right-angled triangles below are

Mathematics
1 answer:
Hoochie [10]2 years ago
3 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\tt{sin(\Theta) = \cfrac{3}{8}}

\qquad \tt \rightarrow \:  x = 6\:\: cm

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  \sin( Theta)  = \cfrac{Opposite \:\: side}{Hypotenuse}

\qquad \tt \rightarrow \:  \sin( \Theta)  =  \cfrac{3}{8}

since the Triangles are similar, ratio of their corresponding sides are equal :

\qquad \tt \rightarrow \:  \sin( \Theta)  =  \cfrac{3}{8}  =  \dfrac{x}{16}

\qquad \tt \rightarrow \:x = 16 \sdot  \cfrac{3}{8}

\qquad \tt \rightarrow \: x = 2 \sdot3

\qquad \tt \rightarrow \: x = 6 \:  \: cm

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Answer:

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Where:

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c = The phase shift

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The given data are;

The amplitude \left | a \right | = 2 feet

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