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julia-pushkina [17]
2 years ago
12

You have 24 homework problems for math class. You finish of them during som

Mathematics
1 answer:
Rudiy272 years ago
4 0

Answer:

Well you can start by dividing 20 by 2 because that would give you the half that you finished in class 24 divided by 2 =12 if you finish four more you wound have 12-4=8 you have 8 problems left and now you have to find the fraction so start with 8/24 and then simplify your answers would be 1/3

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A researcher collected data from a sample of correctional officers and found that on average they made 47,173 dollars a year wit
ollegr [7]

Answer:

a) z = \frac{40000- 47173}{6364} = -1.127

b) z = \frac{50000- 47173}{6364} = 0.444

c) P(X>40000)=P(\frac{X-\mu}{\sigma}>\frac{40000-\mu}{\sigma})=P(Z>\frac{40000-47173}{6364})=P(z>-1.127)

And we can find this probability using the complement rule and the normal standard distribution or excel and we got:

P(z>-1.127)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the amount of money of a population of interet, and we know the following info:  

Where \bar X=47173 and s=6364

We can assume that the sample size is large and the estimators can be used as a good description for the parameters  \mu \sigma

The z score for 40000 would be:

z = \frac{40000- 47173}{6364} = -1.127

Part b

The z score for 50000 would be:

z = \frac{50000- 47173}{6364} = 0.444

Part c

We are interested on this probability

P(X>40000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>40000)=P(\frac{X-\mu}{\sigma}>\frac{40000-\mu}{\sigma})=P(Z>\frac{40000-47173}{6364})=P(z>-1.127)

And we can find this probability using the complement rule and the normal standard distribution or excel and we got:

P(z>-1.127)=1-P(z

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Answer:

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Step-by-step explanation:

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