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koban [17]
2 years ago
5

What are the domain and range of an exponential parent function? Help please

Mathematics
1 answer:
a_sh-v [17]2 years ago
8 0

The domain and the range of an <em>exponential parent</em> function, that is, y = eˣ are equal to all <em>real</em> numbers and <em>non-negative</em> numbers, respectively. (Correct choice: C)

<h3>How to determine the domain and range of an exponential function</h3>

In this problem we should determine what an <em>exponential parent</em> function is. The most common <em>exponential</em> functions have the following form:

y = A\cdot e^{B\cdot x} + C     (1)

(1) is an <em>exponential parent</em> function for A = 1, B = 1 and C = 0.

All functions are relations with a domain and range, the domain is an <em>input</em> set related to the range, that is, an <em>output</em> set. In the case of an <em>exponential parent</em> function, the domain and the range of the expression are \mathbb{R} and y ≥ 0, respectively. (Correct choice: C)

To learn more on exponential functions: brainly.com/question/11487261

#SPJ1

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Write the equation of a line that is parallel to y=0.6x + 3 and that passes through the point (-3,-5)
Mkey [24]

Answer:

\large\boxed{y=0.6x-3.2}

Step-by-step explanation:

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

We have

y=0.6x+3

Parallel lines have the same slope. Therefore we have the equation:

y=0.6x+b

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

-5=0.6(-3)+b

-5=-1.8+b            <em>add 1.8 to both sides</em>

-3.2=b

Finally we have:

y=0.6x-3.2

8 0
3 years ago
Allen has a photo that is 6in by 8in what will the dimension of the photo be if he scales it down by a factor of 1\2
lesantik [10]
A photo of 6 and 8 is scaled down to 1/2 the size
To find this, you multiply both by 1/2 or divide by 2
The new dimensions are 3 by 4
6 divided by 2=3
8 divided by 2=4
6 0
3 years ago
PLS PLS I NEED HELP I HAVE NO TIME I'LL MARK YOU BRAINLIST !!!
Dominik [7]

Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

1)

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

m= 5/2

m= 5/2

y - y1 = m(x - x1)

y - 1 = 5/2(x - 1)

y - 1 = 5/2x - 5/2

y = 5/2x - 3/2

2)

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

m = 2/5

y - y1 = m(x - x1)

y - 0 = 2/5(x - 2)

y = 2/5x - 4/5

5 0
2 years ago
Read 2 more answers
Determine the intercepts of the line. y = 5 x − 1 3 y=5x−13
sweet-ann [11.9K]
Y-intercept = -13
x-intercept = 2.6 or 2 3/5
-13 is the y-intercept. In the equation, y=mx+b, b is the y-intercept. Looking at the equation, y=5x-13, we can see that -13 is in the place of b, therefore -13 is the y-intercept.
() is the x-intercept. To find the x-intercept, you need to replace values into the equation. Since the coordinates for the x-intercept consist of y being 0, you must replace y in the equation. with 0.
0=5x-13
Get rid of the -13 by adding it onto both sides. -13 is negative and the opposite of a negative is positive, thus making you add to get rid of -13.
0=5x-13
+13 +13
13=5x
Now you divide 5 from both sides to get rid of 5. The opposite of multiplication is division, so you must divide the 5 from 5x to isolate the x.
13/5=5x/5
2.6 or 2 3/5=x
Therefore the coordinates (2.6,0) represent the x-intercept, or just 2.6.

I hope this helped.
6 0
3 years ago
What effect does replacing x with x + 2 have on the graph for the function f(x) ?
IrinaK [193]
The answer is A.

When replacing the variable 'x' by 'x + 2' the graph is shifted 2 units to the left. When we replace the variable, the function changes

from
f(x) = |x - 3| + 2

To
f(x) = |(x + 2) - 3| + 2
f(x) = |x - 1| + 2

And therefore the function is shifted 2 to the left.
3 0
3 years ago
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