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2 years ago

What are the domain and range of an exponential parent function? Help please

Mathematics

1 answer:

a_sh-v [17]2 years ago

8 0

The domain and the range of an exponential parent function, that is, y = eˣ are equal to all real numbers and non-negative numbers, respectively. (Correct choice: C)

<h3>How to determine the domain and range of an exponential function</h3>

In this problem we should determine what an exponential parent function is. The most common exponential functions have the following form:

$y = A\cdot e^{B\cdot x} + C$ (1)

(1) is an exponential parent function for A = 1, B = 1 and C = 0.

All functions are relations with a domain and range, the domain is an input set related to the range, that is, an output set. In the case of an exponential parent function, the domain and the range of the expression are $\mathbb{R}$ and y ≥ 0, respectively. (Correct choice: C)

To learn more on exponential functions: brainly.com/question/11487261

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Write the equation of a line that is parallel to y=0.6x + 3 and that passes through the point (-3,-5)

Mkey [24]

Answer:

$\large\boxed{y=0.6x-3.2}$

Step-by-step explanation:

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

We have

$y=0.6x+3$

Parallel lines have the same slope. Therefore we have the equation:

$y=0.6x+b$

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

$-5=0.6(-3)+b$

$-5=-1.8+b$ add 1.8 to both sides

$-3.2=b$

Finally we have:

$y=0.6x-3.2$

8 0

3 years ago

Allen has a photo that is 6in by 8in what will the dimension of the photo be if he scales it down by a factor of 1\2

lesantik [10]

A photo of 6 and 8 is scaled down to 1/2 the size
To find this, you multiply both by 1/2 or divide by 2
The new dimensions are 3 by 4
6 divided by 2=3
8 divided by 2=4

6 0

3 years ago

PLS PLS I NEED HELP I HAVE NO TIME I'LL MARK YOU BRAINLIST !!!

Dominik [7]

Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

m= 5/2

y - y1 = m(x - x1)

y - 1 = 5/2(x - 1)

y - 1 = 5/2x - 5/2

y = 5/2x - 3/2

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

m = 2/5

y - y1 = m(x - x1)

y - 0 = 2/5(x - 2)

y = 2/5x - 4/5

5 0

2 years ago

Read 2 more answers

Determine the intercepts of the line. y = 5 x − 1 3 y=5x−13

sweet-ann [11.9K]

Y-intercept = -13
x-intercept = 2.6 or 2 3/5
-13 is the y-intercept. In the equation, y=mx+b, b is the y-intercept. Looking at the equation, y=5x-13, we can see that -13 is in the place of b, therefore -13 is the y-intercept.
() is the x-intercept. To find the x-intercept, you need to replace values into the equation. Since the coordinates for the x-intercept consist of y being 0, you must replace y in the equation. with 0.
0=5x-13
Get rid of the -13 by adding it onto both sides. -13 is negative and the opposite of a negative is positive, thus making you add to get rid of -13.
0=5x-13
+13 +13
13=5x
Now you divide 5 from both sides to get rid of 5. The opposite of multiplication is division, so you must divide the 5 from 5x to isolate the x.
13/5=5x/5
2.6 or 2 3/5=x
Therefore the coordinates (2.6,0) represent the x-intercept, or just 2.6.

I hope this helped.

6 0

3 years ago

What effect does replacing x with x + 2 have on the graph for the function f(x) ?

IrinaK [193]

The answer is A.

When replacing the variable 'x' by 'x + 2' the graph is shifted 2 units to the left. When we replace the variable, the function changes

from
$f(x) = |x - 3| + 2$

To
$f(x) = |(x + 2) - 3| + 2$
$f(x) = |x - 1| + 2$

And therefore the function is shifted 2 to the left.

3 0

3 years ago