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viktelen [127]
2 years ago
13

Area= in2 Help me please!! Thank you so much

Mathematics
2 answers:
brilliants [131]2 years ago
5 0

Answer:

60 in²

Step-by-step explanation:

<u>Area of a Regular Polygon</u>

  \textsf{A}=\dfrac{n\:s\:a}{2}

where:

  • A = area
  • n = number of sides
  • s = length of one side
  • a = apothem (the line drawn from the center of any polygon to the midpoint of one of the sides)

From inspection of the diagram:

  • n = 5
  • s = 6 in
  • a = 4 in

Substitute the values into the formula and solve for A:

\implies \sf A = \dfrac{5 \times 6 \times 4}{2}

\implies \sf A = \dfrac{120}{2}

\implies \sf A = 60\:in^2

Therefore, the area of the given regular pentagon IJKLM is 60 in².

oee [108]2 years ago
4 0

\huge\text{Hey there!}

\huge\textbf{First thing, let's get the formula for}\\\huge\textbf{the regular pentagon/polygon.}

\mathbf{\dfrac{1}{2}\times \boxed{a}pothem\times\boxed{p}erimeter = {\boxed{a}rea}}

\huge\textbf{Or we could simply say....}

\mathbf{\dfrac{\boxed{n}umber\ of\ sides\ you\ have \times \boxed{s}ide \ length\ on\ one\ side\times \boxed{a}pothem}{2} = \boxed{a}rea}

\huge\textbf{Let's plug the pieces to the equation,}\\\huge\textbf{since we have that information out the}\\\huge\textbf{way.}

\bullet\mathbf{\ Number\ of\ sides \rightarrow \boxed{\bf 5}}

\bullet\mathbf{\ Side\ length\ of\ one\ side \rightarrow \boxed{\bf 6\ inches}}

\bullet\mathbf{\ Apothem \rightarrow  \boxed{\bf 4\ inches}}

\huge\textbf{Making the equation for you:}

\mathbf{\dfrac{5\times 6 \times 4}{2} = \boxed{a}rea}

\huge\textbf{Solving for the result:}

\mathbf{\dfrac{5\times 6 \times 4}{2} = \boxed{a}rea}

\mathbf{\dfrac{30\times 4}{2} = \boxed{a}rea}

\mathbf{\dfrac{120}{2} =\boxed{a}rea}

\mathbf{\dfrac{120\div2}{2\div2} = \boxed{a}rea}

\mathbf{\dfrac{60}{1} = \boxed{a}rea}

\mathbf{60\div1 = \boxed{a}rea}

\mathbf{60 = \boxed{a}rea}

\huge\textbf{Met the result....}

\huge\text{Thus, your answer should be: \boxed{\mathsf{60\ in^2}}}\huge\checkmark

\huge\text{Good luck on your assingment \& enjoy your day!}

<h3>~\frak{Amphitrite1040:)}</h3>
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