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alukav5142 [94]
3 years ago
12

The sum of three numbers is 108. The second number is four times greater than the first number, and the third number is 18 more

than the first. Find the largest of the three numbers.
Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

450

Step-by-step explanation:

108 x 4 +18

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Write the equation of the line, given the y and x-intercepts.
Dimas [21]

Answer:

y = -(2/3)m - 2

Step-by-step explanation:

recall that the general equation of a straight line in slope-intercept form is

y = mx + b

where, m is the slope and b is the y - intercept

here we are given that the y - intercept is -2, hence the equation becomes:

y = mx + (-2)

or

y = mx -2

we are also given that the x-intercept is -3, which means that when y = 0, x = -3 (simply substitute this into our new equation to solve for m)

0 = m(-3) -2

0 = -3m - 2  (add 3m to both sides)

3m = -2  (divide both sides by 3)

m = -(2/3)

hence our equation is now

y = -(2/3)m - 2

5 0
3 years ago
6. Juan recibe de su papá, quien tiene un negocio de maquinitas, su mesada semanal de $62.000 en monedas de $200,
Y_Kistochka [10]

Answer:

15100

Step-by-step explanation:

7 0
3 years ago
To calculate the number of montly payments required to pay off a loan or meet an investment goal, use the _______ function.
soldier1979 [14.2K]
NPER function

Hope this helps... mark as Brainliest plz
7 0
3 years ago
8. A substance has a half life of 2.347 minutes.
mina [271]

Answer:

a.) 4 half lives have passed

b) 9.388 minutes

Step-by-step explanation:

Formula for exponential growth / decay is given as:

A=A_0b^{\frac{t}{c}}

Where A is the final population

A_0 is the initial population

b is the growth factor

c is the time taken for the growth 'b'

t is the amount of time

Here, we are given that:

A = 6. 9 grams

A_0 = 110.4 grams

b = \dfrac{1}{2}

c = 2.347 min

To find:

a.) Number of half lives taken for the decay.

b.) Total time in the decay.

Solution:

a.) Number of half lives taken for the decay is nothing but equal to \frac{t}{c}.

Putting the values in the formula, we get:

6.9=110.4\times \frac{1}2^{\frac{t}{c}}\\\Rightarrow 6.9=110.4\times 0.5^{\frac{t}{c}}\\\Rightarrow 0.0625=0.5^{\frac{t}{c}}\\\Rightarrow \dfrac{t}{c} =4

Therefore, the answer is:

<em>4 half lives </em>have passed.

b.) Total time of decay. We have to find the value of t here.

From answer of part a.):

\dfrac{t}{c} =4\\\Rightarrow \dfrac{t}{2.347} =4\\\Rightarrow t =\bold{9.388\ min}

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3 years ago
Compare the linear functions expressed below by data in a table and by an equation.
Dahasolnce [82]

Answer:

B, C, and E

Just took the test

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3 years ago
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