Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
Answer:
(0,5)
Step-by-step explanation:
If you plug in 0 in all the variables of x, f(x)=0+0+5
We know that f(x) is y...so y=5, while x=0
Answer: 11:12 PM.
explanation:
- 10% of 8 is 0.8. (10% is 0.1, and you multiply this by 8)
- multiply 0.8 by 60 so you can get the number of minutes before midnight (this is 48).
- 48 minutes before midnight is 11:12.
Answer:
m∠1 = 89°
Step-by-step explanation:
Since m∠2 is a part of ∠GFH, he can do the following.
∠GFH - m∠2 = m∠1
133° - 44° = 89°
