Answer:
22.7604763 degrees
Step-by-step explanation:
Note that the answer is NOT 20 degrees.
She adjusted the ramp to half the original <em>incline</em>
Therefore we have tan 40 = x = 0.839099631.
We want an incline of y degrees where tan y = x/2 = 0.839099631/2 = 0.419549815
Taking the arctan of both sides, we get
y = arctan(0.419549815) = 22.7604763 degrees
Answer:
(four being the slope)
Step-by-step explanation:
So lets use
ΔY/ΔX
or the y2-y1 over x2-x1


Therefore, the slope is 4
The length of each side of the polygon is the number of units on each side of the polygon, and the perimeter of the factory is 1000 feet
<h3>The length of each side of the polygon?</h3>
To do this, we simply calculate the number of units on each side of the polygon.
So, we have:
S1 = 5 units
S2 = 8 units
N1 = 13 units
E1 = 7 units
W1 = 3 units
W2 = 4 units
<h3>The perimeter of the polygon</h3>
This is the sum of the side lengths.
So, we have:
Perimeter = 5 + 8 + 13 + 7 + 3 + 4
Perimeter = 40
Each unit equals 25 feet.
So, we have:
Perimeter = 40 * 25 feet
Evaluate
Perimeter = 1000 feet
Hence, the perimeter of the factor is 1000 feet
Read more about perimeter at:
brainly.com/question/24571594
#SPJ2
Answer:
-3.6
Step-by-step explanation:
Simplifying
7 + 3x + 4 = 0
Reorder the terms:
7 + 4 + 3x = 0
Combine like terms: 7 + 4 = 11
11 + 3x = 0
Solving
11 + 3x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-11' to each side of the equation.
11 + -11 + 3x = 0 + -11
Combine like terms: 11 + -11 = 0
0 + 3x = 0 + -11
3x = 0 + -11
Combine like terms: 0 + -11 = -11
3x = -11
Divide each side by '3'.
x = -3.666666667
Simplifying
x = -3.666666667
Square part of perimeter = 40.
Half circle = 25.135.
Together 65.135 is perimeter.
Area of square: 192
Are of half circle: 100.53.
Together 292.53
Rounded =292.48 I guess, its the most logical option since I don't see it and the only one that fits perimeter answer.
So its the 3rd question I believe, you may want to double check.
Hit the heart if it was helpful.