Answer:
78% probability it contains no defects
Step-by-step explanation:
We have that:
10% have defects in shafts only.
8% have defects in bushings only.
4% have the two types of defects.
An assembly is selected arandom, what is the probability it contains no defects
Either it has at least one defect, or it has no defects. The sum of these probabilities is 100%. So
D + ND = 100
Probability that it has a defect
D = 10 + 8 +4 = 22%
No defects:
22 + ND = 100
ND = 78
78% probability it contains no defects
<u>ANSWER:
</u>
After changing the side lengths of the triangle are decreased by scale factor of 3, the perimeter of triangle also decreased by 3
<u>SOLUTION:</u>
Given, the side lengths of a triangle are decreased by a scale factor of 3.
Let the side lengths of the given triangle be a, b, c.
After the side lengths are decreased by a scale factor of 3.
Now, the side lengths will become 
Before changing the side lengths, perimeter of the triangle is p = a + b + c.
After changing the side lengths, perimeter of the triangle is 
So, the perimeter is also decreased by the scale factor of 3.
Hence, after changing the side lengths of the triangle are decreased by scale factor of 3, the perimeter of triangle also decreased by 3.
Probably let x be 8 and y be 2
Then you input the values
8-2=6
Then
2(8)-10(2)
=16-20
=-4
How they have 4?!
Answer:
Mean qualifying speed
= 224.5669mi/hr
Speed that passed the average/mean
= 226.240mi/hr ,224.037mi/hr 226.484mi/hr, 225.172 mi/hr
Step-by-step explanation:
Let's understand what mean is then understand what mean qualifying speed is.
First mean is like the average of the seven speed listed below.
So let's find the mean.
Mean = (223.684+ 222.929+ 226.240
+224.037 +226.484+ 225.172
+223.422)/7
Mean = 1571.968/7
Mean = 224.5669
So the mean qualifying speed is those speed that qualifies when the mean is taken, i.e the speed that crossed the average.
Mean qualifying speed are
=226.240 ,224.037,226.484
, 225.172
