Question

Multiply Conjugates Using the Product of Conjugates Pattern

Answer 1

Answer:

The product is the difference of squares is$\left(4-6y\right)\left(4+6y\right)=16-36{{y}^2}$

Step-by-step explanation:

Explanation

• The given expression is (4-6 y)(4+6y).

• We have to multiply the given expression.

• Square the first term 4. Square the last term 6y.

$\begin{aligned}&(4-6 y)(4+6 y)=(4)^{2}-(6 y)^{2} \\&(4-6 y)(4+6 y)=16-36 y^{2}\end{aligned}$