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CaHeK987 [17]
2 years ago
15

Multiply Conjugates Using the Product of Conjugates Pattern

Mathematics
1 answer:
Harrizon [31]2 years ago
7 0

Answer:

The product is the difference of squares is$$\left(4-6y\right)\left(4+6y\right)=16-36{{y}^2}$$

Step-by-step explanation:

Explanation

  • The given expression is (4-6 y)(4+6y).
  • We have to multiply the given expression.
  • Square the first term 4. Square the last term 6y.

$$\begin{aligned}&(4-6 y)(4+6 y)=(4)^{2}-(6 y)^{2} \\&(4-6 y)(4+6 y)=16-36 y^{2}\end{aligned}$$

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