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tankabanditka [31]
2 years ago
10

How many moles of oxygen gas (02) are

Chemistry
1 answer:
ZanzabumX [31]2 years ago
7 0

The number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.

<h3>Number of moles of the reacting aluminum </h3>

moles = reacting mass/molar mass

moles = 54/27

moles = 2 moles

From the given reaction of oxygen and aluminum;

4Al +  30₂   →   2Al₂O₃

4 moles of Al ----------> 3 moles of oxygen

2 moles of AL --------> ? moles of oxygen

= (2 x 3)/4

=  1.5 moles

Thus, the number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.

Learn more about number of moles here: brainly.com/question/15356425

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Answer:

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Explanation:

Step 1: Given data

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  • Room temperature (T): 23 °C
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Step 2: Convert "T" to Kelvin

We will use the following expression.

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We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

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The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

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