Answer:
CH₃CH₂CH₂COOH.
Explanation:
To know which option is correct, let us hydrolysed the given ester. This is illustrated in the attached photo.
Hydrolysis of ester involves breaking the ester bond by a water molecule to produce the corresponding alcohol and carboxylic acid.
From the reaction given in the attached photo, we can see that the carboxylic acid needed to produce the desired ester is butanoic acid, CH₃CH₂CH₂COOH.
Write the balanced neutralization reaction<span> between H2SO4(</span>sulfuric acid<span>) and </span>KOH(potassium hydroxide<span>) in </span>aqueous<span> solution. 0.150L of 0.470 M H2SO4 is mixed with 0.100L of 0.230 M </span>KOH<span>.</span>
To solve this problem, we make use of the Faraday’s law
for Electrolysis. The formula is given as:
I t = m F / e
where the variables are,
I = current = 24.4 A
t = time = 46 min = 2760 s
m = mass produced = (unknown)
F = Faraday’s constant = 96500 C/equivalent
e = gram equivalent weight of gold
The gram equivalent weight is calculated by dividing the
molar mass with the amount of charge produced per atom. Gold has charge of 3+
therefore the gram equivalent weight is:
e = (196.97 g/mol)(1 mol/3 equivalents) = 65.66
g/equivalents
Solving for the mass m:
m = e I t / F
m = (65.66 g) (24.4 A) (2760 s) / (96500 C)
m = 45.82 g
Answer:
D
Explanation:
Gibb's free energy change(∆G) and Standard electrode potential of electrochemical (Ecell) determine the spontaneity of a reaction.
when ∆G > 0, the reaction is not spontaneous
∆G < 0, the reaction is spontaneous
∆G = 0, the reaction is in equilibrium
when Ecell > 0, the redox reaction is spontaneous
Ecell < 0, the redox reaction is not spontaneous
Ecell = 0, the redox reaction is in equilibrium.