Question

For the function below, list 4 ordered pairs for that function. y = 3x + 1

Answer 1

Answer:

(1, 4)

(2, 7)

(0, 1)

(-1, -2)

Explanation:

to find ordered pairs, we plug in different values for x.

(remember, and "ordered pair" is (x, y)--the first number turns into the second number when put through the function)

usually, it's easiest to plug in smaller numbers, so that it is less complicated to graph

so, here's a few x values:

x = 1

y = 3x + 1

y = 3(1) + 1

y = 3 + 1

y = 4

so, when x = 1, y = 4

we write this as: (1, 4)

x = 2

y = 3x + 1

y = 3(2) + 1

y = 6 + 1

y = 7

so, when x = 2, y = 7

we write this as: (2, 7)

x = 0

y = 3x + 1

y = 3(0) + 1

y = 0 + 1

y = 1

so, when x = 0, y = 1

we write this as: (0, 1)

x = -1

y = 3x + 1

y = 3(-1) + 1

y = -3 + 1

y = -2

so, when x = -1, y = -2

we write this as: (-1, -2)

hope this helps!! have a lovely day :)