Add 3x to 4 a. 7x b. 7 c. 34x d. 4+3x

Help please!!! I dont understand these questions currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

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4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

Which method of gathering data is described by the statement "these are run only when probabilities are known as fact

HACTEHA [7]

It seems that you have missed the necessary options for us to answer this question. But anyway, here is the answer. The method of gathering data that is described by the statement "these are run only when probabilities are known as fact" is called SIMULATION. Hope this answers your question.

3 0

3 years ago

Rewrite the polynomial in the form ax^2+bx+c and then identify the values of a, b, and c. 6+9x^2

Ulleksa [173]

Answer:

see below

Step-by-step explanation:

6+9x^2

Rewriting in decreasing powers of x

9x^2 +0x + 6

ax^2+bx+c

a = 9

b =0

c = 6

5 0

3 years ago

The temperatures at several times of the day are shown in the coordinate plane below. The x-axis represents the number of hours

Drupady [299]

Question:

The temperatures at several times of the day are shown in the coordinate plane below. The x-axis represents the number of hours before or afternoon. For example, -1 would represent 11 a.m. The y-axis represents the temperature in degrees Celsius.At 5 p.m, the temperature is halfway between the temperature at 2 p.m. and the temperature at 8 p.m.

What coordinates represent the temperature at 5 p.m.?

Answer:

(5, 2)

=> At 5pm, the temperature is at 2⁰C

Step-by-step Explanation:

Coordinates of any point on a cartesian/coordinate plane is represented by (x, y). Where x is the number at the point on z-axis, while y is the number at the same point on the y-axis.

From the diagram of the coordinate plane attached below, we can simply find out what coordinates represent the temperature at 5pm.

==> Given that the temperature at 5pm is half way between the temperature at 2pm (y=7) and temperature at 8pm (y=-3), the point that is being referred to = [7+(-3)] ÷ 2 = ⁴/2 = 2 (i.e. 2 on the y axis representing temperature)

*The position of the point is indicated in the second picture that is attached below.

At that position of the point, we have 2 as the coordinate for the y axis representing temperature, and at that same position, we have 5 on the x-axis representing the number of hours.

Therefore, coordinates of the point (x, y) representing 5p.m = (5, 2)

==> At 5pm, the temperature is at 2⁰C