None they are parallel lines - same slope different y intercept
They all only have 1 term.
Hello There!! (:
I'm Here to help!
If we say Kelly orders 1 chicken salad, then it means she ordered 5 egg salads.
If she ordered x chicken salads, then she'll have to order the rest, which is <span>(6−x)</span> egg salads.
For first equation, let's set y to be the meal's price. It consist of the price of all chicken salads ordered and the price of all egg salads ordered:
<span>y=5x+4(6−x)</span>
Again, x represents number of chicken salads ordered, and y represents the meal's price.
A second equation would come to limit the price to the money Kelly has:
<span>y≤28
</span>
Notice there are more constraints to add on the values (x cannot be negative, no such thing negative number of salads or fractional number of salads) so just keep that in mind.
Now, since we know the price based on the number of chicken salads, we can say for what number of salads it matches the second restriction:
<span><span><span>5x+4(6−x)≤28</span><span>5x+24−4x≤28</span><span>x≤28−24</span><span>x≤4
Does this help you?
I Sure hope so have a goodnight ! (:
</span></span></span>
Answer:
fog = 2√(x-1) + 1
Domain = [1, 
)
Step-by-step explanation:
Given the functions f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog
fog = f(g(x))
f(g(x)) = f(√(x-1))
f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)
f(√(x-1)) = 2(√(x-1))+1
f(√(x+1)) = 2√(x-1) + 1
fog = 2√(x-1) + 1
<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>
If x-1≥0
x≥0+1
x≥1
This means the range of variable x must be values of x greater than or equal to 1.
Domain = [1, )
