Answer:
l = 16, w = 8
Step-by-step explanation:
Let l = length
Let w = width
Area = w * l
128 = w * l
w = 128/l
Perimeter = 2w + 2l
48 = 2w + 2l
48 = 2(128/l) +2l
48 = 256/l +2l
Multiply everything by l
48l = 256 + 2l^2
l^2 + 128 = 24l
l^2 + 128 -24l = 0
(l-16)(l-8)= 0
L = 16
L = 8
If you try them out, and test it, l = 16 would work:
2(16) + 256/16 = 48
32 + 16 =48
16 * 128/16 = 128
16 * 8= 128
128 = 128
Since I'm not sure if you are in advanced math or not, I will do it simple with guess and check
Try w is
For 3 it’s b. For 2 it’s 8. For 4 it’s the whole number
find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
Izzy because her word rate is 98, which is more than 95 (the minimum).