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sergiy2304 [10]
3 years ago
10

What is 1+1? I am so confused in this

Mathematics
1 answer:
ladessa [460]3 years ago
8 0

Hello from MrBillDoesMath!

Answer:

2


Discussion:

1 + 1  = 2

Regards,  

MrB


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Charlotte has to read a book for school. There are 513 pages in the book. She read 113 pages on
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The answer is A. 221 pages.
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3 years ago
Suppose that you are playing blackjack against a dealer. in a freshly shuffled deck, what is the probability that neither you no
guapka [62]

The probability that neither you nor the dealer is dealt a blackjack will be 1/26.

<h3>What is probability?</h3>

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

Suppose that you are playing blackjack against a dealer. In a freshly shuffled deck.

Then the total number of the event will be

Total events = 52

Then the probability that neither you nor the dealer is dealt a blackjack will be

Favorable event = 2 {Spade of Jack and Club of Jack}

Then the probability of that events will be

P = 2 / 52

P = 1 / 26

The probability that neither you nor the dealer is dealt a blackjack will be 1/26.

More about the probability link is given below.

brainly.com/question/795909

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8 0
2 years ago
Find the flux of F = x^3 i  + y^3 j  + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4
givi [52]
Use the divergence theorem. Let R be the cylindrical region, then

\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV

(where \mathbf n denotes the unit normal vector to \partial R, but we don't need to worry about it now)

We have

\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}
\nabla\cdot\mathbf F=3x^2+3y^2+3z^2

For the solid R with boundary \partial R, we can set up the following volume integral in cylindrical coordinates for ease:

\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz
=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz
=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz
=352\pi
5 0
3 years ago
Find cos(sin-1(3/5))
Natali5045456 [20]
Sin-1 (3/5) = 36.869
cos 3/5 = 0.999
8 0
3 years ago
Matt has soccer practice on May 4th you will practice every fourth day after that I can't begins baseball practice every third d
vovikov84 [41]

Answer:

May 12th

Step-by-step explanation:

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3 years ago
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