What is 1+1? I am so confused in this

Mathematics

1 answer:

ladessa [460]3 years ago

8 0

Hello from MrBillDoesMath!

Answer:

Discussion:

1 + 1 = 2

Regards,

MrB

You might be interested in

Charlotte has to read a book for school. There are 513 pages in the book. She read 113 pages on

Delicious77 [7]

The answer is A. 221 pages.

5 0

3 years ago

Suppose that you are playing blackjack against a dealer. in a freshly shuffled deck, what is the probability that neither you no

guapka [62]

The probability that neither you nor the dealer is dealt a blackjack will be 1/26.

<h3>What is probability?</h3>

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

Suppose that you are playing blackjack against a dealer. In a freshly shuffled deck.

Then the total number of the event will be

Total events = 52

Then the probability that neither you nor the dealer is dealt a blackjack will be

Favorable event = 2 {Spade of Jack and Club of Jack}

Then the probability of that events will be

P = 2 / 52

P = 1 / 26

The probability that neither you nor the dealer is dealt a blackjack will be 1/26.

More about the probability link is given below.

brainly.com/question/795909

#SPJ4

8 0

2 years ago

Find the flux of F = x^3 i + y^3 j + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4

givi [52]

Use the divergence theorem. Let $R$ be the cylindrical region, then

$\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV$

(where $\mathbf n$ denotes the unit normal vector to $\partial R$ , but we don't need to worry about it now)

We have

$\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}$
$\nabla\cdot\mathbf F=3x^2+3y^2+3z^2$

For the solid $R$ with boundary $\partial R$ , we can set up the following volume integral in cylindrical coordinates for ease:

$\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$
$=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz$
$=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz$
$=352\pi$