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Elena-2011 [213]
1 year ago
14

*Need Help*Match each rational expression to its simplest form.

Mathematics
1 answer:
Stella [2.4K]1 year ago
4 0
The first expression goes into m - 1
the second expression is m - 2 / m
and the last expression goes m - 2 / m - 1
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Is the relation shown in the arrow diagram a function?
Irina-Kira [14]

Answer:

Yes. Every unique input has a unique output.

Step-by-step explanation:

Since every input has a different output, therefore it's a function. It's not a function when the input have more than 1 output. When graphing, make sure you take the vertical line test to see whether or not the graph is a function.

4 0
2 years ago
Help!1!1!1 ASAP please !1!1
gulaghasi [49]

Answer:

1/4 Teaspoons: 7

1/3 Cup: 20

Step-by-step explanation:

1/3 Cup:

Butter (2), Sugar (4), Coca (3), Flour(11)

1/4 Teaspoon:

Salt (3), Baking Soda (4)

4 0
3 years ago
Read 2 more answers
Please help ...........
viva [34]
I believe the answer is d
7 0
3 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
2 years ago
Can someone show me how to do this problem and I need help!! <br><br> Thank you!!
UNO [17]

Answer:

\frac{6}{19 }

Step-by-step explanation:

6 + 5 + 7 + 1 + 0 = 19

4 0
3 years ago
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