The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
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Answer:
A. Playfair's axiom.
Step-by-step explanation:
In a plane, given a line and a point not on it, at most, one line parallel to the given line can be drawn through the point.
- this implies Euclid's fifth postulate.
30-(11+(18-(48/8×2))+7)+15
= 30-(11+(18-12)+7)+15
= 30-(11+6+7)+15
= 30-24+15
= 21
Thge answer id the first one or last one