The degree is 3, the zeros are; 4, 2i, -2i and a point is (-48, 2)
For zeros; 2i, -2i <-- complex conjugates, always in pairs

= -4(i²=-1)
=5

=0
Therefore the equation is; a(

+5) <-- b value is zero
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
1. Solve for N
Add all terms together and set equal to 360
(4n)+(9n+2)+(8n-12)+(5n+6)=360
26N= 364
N= 14
M<A = 4(14)= 56
2.9(14)+2=128
3. 8(14)-12= 100
4. 76
Answer:
The correct option is B. 16.3
Step-by-step explanation:
We are given a vector with components
V = 36x +33y
To solve this problem, we find its magnitude
|V| = SQRT (36^2 + 33^2)
|V| = SQRT (2385)
|V| = 48.836
To find the magnitude of the new vector we divide by three the previous quantity
|V2| = 48.836/3 = 16.278
The correct answer is 2.86
There's not enough information to solve this.