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In-s [12.5K]
3 years ago
7

a team played 99 games. if they won 15 more than twice as many games as they loss how many wins and losses did they have.

Mathematics
1 answer:
rusak2 [61]3 years ago
3 0
Lost 26
Won 67
Total 93
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In the expression 2x-15, what is the variable being used ?
erma4kov [3.2K]

Isn't x the variable?

6 0
3 years ago
(2b) A rectangular prism measures 2 & 2/5 inches by 3 & 1/5 inches by 2 inches. How many cubes with edge length 1/5 inch
erastova [34]

Answer:

1920 cubes.

Step-by-step explanation

Turn both the mix numbers into improper fractions.

2 2/5 = 12/5

3 1/5 = 16/5

Then you will turn 1/5 into its reciprocal and multiply both the improper fractions by it. You can just casually multiply 2 and 5.

12/5 * 5/1 = 12

16/5 * 5/1 = 16

2 * 5 = 10

Next you multiply all together to get 1920 cubes.

(I could be missing a step. I apologize if I did.)

3 0
3 years ago
Find 2/5 of 128. I need help
hammer [34]
So you would multiply if it has the word of in the problem right?

4 0
3 years ago
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
What is the equation of a line that has a slope of -1/2 and contains the point (8,1)?
Troyanec [42]

(\stackrel{x_1}{8}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-\cfrac{1}{2}}(x-\stackrel{x_1}{8}) \\\\\\ y-1=-\cfrac{1}{2}x+4\implies y=-\cfrac{1}{2}x+5

3 0
2 years ago
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